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sergejj [24]
2 years ago
14

What do you know in climate change?​

Physics
1 answer:
Degger [83]2 years ago
7 0

Climate change is the reason for a lot of factors such as:

Heat-trapping Greenhouse Gases And The Earth's Climate

Greenhouse Gases

Reflectivity or Absorption of the Sun's Energy

Changes in the Earth's Orbit and Rotation

Variations in Solar Activity

Changes in the Earth's Reflectivity

Volcanic Activity

There's a lot more that I could list, but hopefully this will do.

You might be interested in
3. Light travels from the Sun to Earth in 8.3 min. Given that the speed of light is 3.00108 m/s, what is the distance in meters
nasty-shy [4]

Answer:

13

Explanation:

13.0120481928 it is the distance

4 0
3 years ago
A box with a mass of 40 kg sits at rest on a frictionless tile floor. with your foot, you apply a 20 N force in a horizontal dir
Grace [21]

Answer:

0.5 m/s²

Explanation:

according to Newton's second law, we are goven a relationship between force, mass and acceleration, with the formula:

F = m×a

F for force

m for mass

a for acceleration

we use the given data and get:

20 = 40×a

we find a=20/40=0.5m/s²

4 0
2 years ago
Read 2 more answers
A 20-kg barrel is rolled up a 20-m ramp to the back of a truck whose floor is 5.0 m above the ground. What work is done in loadi
oee [108]

The angle of inclination is calculated using sin function,

sin θ = 5 m / 20 m = 0.25

θ = 14.4775° 

 

<span>The net force exerted is then calculated:
F net = m g sin θ = 20 * 9.8 * 0.25 </span>

F net = 49N 

<span>Work is product of net force and distance:
W = F net * d = 49 * 20 </span>

<span>Work = 980 J </span>

4 0
3 years ago
Round to the hundredths place.
Ivanshal [37]

Answer:

21 protons

Explanation:

4 0
3 years ago
The activity of a radioisotope is found to decrease 40% of its original value in 2.59 x 10 s.
Rainbow [258]

Answer: 0.0353\ s^{-1}

Explanation:

Given

Radioactive material is found to decrease 40% of its original value in 2.59\times 10\ s

Sample at any time is given by

N=N_oe^{-\lambda t}

where, \lambda=\text{decay constant}

Put values

\Rightarrow 0.4N_o=N_oe^{-\lambda\cdot 2.59\times 10}\\\Rightarrow 0.4=e^{-\lambda\cdot 2.59\times 10

Taking natural logarithm both side

\Rightarrow \lambda=\dfrac{\ln 2.5}{25.9}\\\\\Rightarrow \lambda =0.0353\ s^{-1}

8 0
3 years ago
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