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3 years ago

What is the frequency of a clock waveform whose period is 750 microseconds?

Physics

1 answer:

Allushta [10]3 years ago

6 0

Use this formula to find your answer...

Determine the frequency of a clock waveform whose period is 2us or (micro) and 0.75ms

frequency (f)=1/( Time period).

Frequency of 2 us clock =1/2*10^-6 =10^6/2 =500000Hz =500 kHz.

Frequency of 0..75ms clock =1/0.75*10^-3 =10^3/0.75 =1333.33Hz =1.33kHz.

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A car is behind a truck going 25 m/s on the highway. The car’s driver looks for an opportunity to pass, guessing that his car ca

user100 [1]

Answer:

No he should not attempt the pass

Explanation:

Let t be the time it takes for the car to pass the truck. The driver should ONLY attempt to pass when the distance covered by himself plus the distance covered by the oncoming car is less than or equal 400 m (a near miss)

At acceleration of 1m/s2 and a clear distance of 10 + 20 + 10 = 40 m, we can use the following equation of motion to estimate the time t in seconds

$s = at^2/2$

$40 = 1t^2/2$

$t^2 = 80$

$t = \sqrt{80} = 8.94 s$

Within this time frame, the first car would have traveled a total distance of the clear distance (40m) plus the distance run by the truck, which is

8.94 * 25 = 223.6m

So the total distance traveled by the first car is 223.6 + 40 = 263.6m

The distance traveled by the 2nd car within 8.94 s at rate of 25m/s is

8.94 * 25 = 223.6 m

So the total distance covered by both cars within this time frame

223.6 + 263.6 = 487.2m > 400 m

So no, he should not attempt the pass as we will not clear it in time.

8 0

3 years ago

Which of these is most likely a step in the formation of soil? a. erosion of soil b. crystallization of rocks c. animals digging

Lyrx [107]

C. Measure the soil's volume and then the volume of water that the soil can absorb.

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3 years ago

Read 2 more answers

Can you think of a scenario when the kinetic and gravitational potential energy could both be zero ? Describe or draw how this c

Inga [223]

Both kinetic and gravitational potential energy can become zero at infinite distance from the Earth.

Consider an object of mass m projected from the surface of the Earth with a velocity v.

The total energy of the body on the surface of the Earth is the sum of its kinetic energy $\frac{1}{2} mv^2$ and gravitational potential energy $-\frac{GMm}{R^2}$ .

here, M is the mass of the Earth, R is the radius of Earth and G is the universal gravitational constant.

The gravitational potential energy of the object is negative since it is in an attractive field, which is the gravitational field of the Earth.

The energy of the object on the surface of the earth is given by,

$E_i=\frac{1}{2} mv^2-\frac{GMm}{R^2}$

As the object rises upwards, it experiences deceleration due to the gravitational force of the Earth. Its velocity decreases and hence its kinetic energy decreases.

The decrease in kinetic energy is manifested as an equal increase in potential energy. The potential energy becomes less and less negative as more and more kinetic energy is converted into potential energy.

At a height h from the surface of the Earth, the energy of the object is given by,

$E_h=\frac{1}{2} mv_h^2-\frac{GMm}{(R+h)^2}$

The velocity $v_h$ is less than v.

When h =∞, the gravitational potential energy increases from a negative value to zero.

If the velocity of projection is adjusted in such a manner that the velocity decreases to zero at infinite distance from the earth, the object's kinetic energy also becomes equal to zero.

Thus, it is possible for both kinetic and potential energies to be zero at infinite distance from the Earth. In this case, kinetic energy decreases from a positive value to zero and the gravitational potential energy increases from a negative value to zero.

7 0

3 years ago

How much Tim in minutes will it take a car driving at 90km/hr to travel 27 kilometers

astraxan [27]

Answer:

18min

Explanation:

v=d/t

t=d/v= 27/90 =0.3hrs =18min

6 0

3 years ago

The components of vector A are:

Korvikt [17]

here as it is given that x component of the vector is positive while y component of the vector is negative so we can say the vector must inclined in Fourth quadrant.

So angle must be more than 270 degree and less than 360 degree

Now in order to find the value we can say that

$tan\theta = \frac{opposite\: side}{adjacent\: side}$