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ddd [48]
3 years ago
8

What is the frequency of a clock waveform whose period is 750 microseconds?

Physics
1 answer:
Allushta [10]3 years ago
6 0
Use this formula to find your answer...

Determine the frequency of a clock waveform whose period is 2us or (micro) and 0.75ms

frequency (f)=1/( Time period).

Frequency of 2 us clock =1/2*10^-6 =10^6/2 =500000Hz =500 kHz.

Frequency of 0..75ms clock =1/0.75*10^-3 =10^3/0.75 =1333.33Hz =1.33kHz.

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The acceleration of a particle traveling along a straight line isa=14s1/2m/s2, wheresis in meters. Ifv= 0,s= 1 m whent= 0, deter
Yuliya22 [10]

Answer:

0.78m/s

Explanation:

We are given that

Acceleration=a=\frac{1}{4}s^{\frac{1}{2}}m/s^2

v=0, s=1 when t=0

We have to find the particle's velocity at s=2m

We know that

a=\frac{dv}{dt}=\frac{dv}{ds}\times \frac{ds}{dt}=\frac{dv}{ds}v

vdv=ads

\int_{0}^{v} vdv=\int_{1}^{s}0.25s^{\frac{1}{2}}ds

\frac{v^2}{2}=0.25\times \frac{2}{3}(s^{\frac{3}{2})^{s}_{1}

By using formula:\int x^ndx=\frac{x^{n+1}}{n+1}+C

\frac{v^2}{2}=0.25\times \frac{2}{3}(s^{\frac{3}{2}}-1

Substitute s=2

\frac{v^2}{2}=\frac{0.50}{3}((2^{1.5})-1)

\frac{v^2}{2}=\frac{0.50}{3}\times 1.83

v^2=2\times 0.305=0.61

v=\sqrt{0.61}=0.78m/s

Hence, the velocity of particle at s=2m=0.78m/s

3 0
4 years ago
Why does the density of a substance remain the same for different amount of the substance
tresset_1 [31]

Think of it this way: 
-- Any time you have something that means (some number) PER UNIT,
it doesn't matter how many units there are on the table or in the bucket,
because that amount doesn't change the (number) PER UNIT.

-- If oranges cost $1 PER POUND, it doesn't matter how many pounds
you buy, the whole bagful is still $1 PER POUND.

-- If a certain salad dressing has 40 calories PER Tablespoon, it doesn't
matter whether you eat a drop of it or drink the whole jar.  You still get
40 calories PER Tablespoon.

-- Density means '(mass) PER unit of volume'.  Whether you have a tiny
chip of the substance or a whole truckload of it, there's still the same
amount of mass IN EACH unit of volume.

6 0
3 years ago
Heptane and water do not mix, and heptane has a lower density (0.684 g/mL) than water (1.00 g/mL). A graduated cylinder contains
lakkis [162]

Given that the density of heptane is

d_h=\frac{0.684g}{mL}

The mass of heptane is

m_h=31\text{ g}

The density of water is

d_w=\frac{1g}{mL}

The mass of water is

m_w=37\text{ g}

The volume of heptane will be

\begin{gathered} V_h=\frac{m_h}{d_h} \\ =\frac{31}{0.684} \\ =45.32\text{ mL} \end{gathered}

The volume of water will be

\begin{gathered} V_w=\frac{m_w}{d_w} \\ =\frac{37}{1} \\ =37\text{ mL} \end{gathered}

Thus, the volume of heptane is 45.32 mL and the volume of water is 37 mL.

The total volume of liquid in the cylinder will be

\begin{gathered} V=V_h+V_w \\ =45.32+37 \\ =82.32\text{ mL} \end{gathered}

The total volume of liquid in the cylinder will be 82.32 mL.

7 0
1 year ago
How can people reconcile technology with environmental preservation?​
MatroZZZ [7]
1. Developing renewable energy technology

- Efficient energy storage and smarter grids .
- renewable and rechargeable batteries and fuel cell

2. Saving endangered wildlife

-smart collars for endangered species and reducing human - animal conflict
-Gene sequencing for detecting and researching on deadly animal diseases.

3. Adopting a smarter lifestyle

- smart homes that promote energy saving and green - living .
- electric cars which are three times more conventional vehicles .

Hope this helps :)
5 0
3 years ago
Whats the answer to 45 + 54 ÷ p - q
Lynna [10]
There’s nothing to answer to
4 0
3 years ago
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