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ddd [48]
3 years ago
8

What is the frequency of a clock waveform whose period is 750 microseconds?

Physics
1 answer:
Allushta [10]3 years ago
6 0
Use this formula to find your answer...

Determine the frequency of a clock waveform whose period is 2us or (micro) and 0.75ms

frequency (f)=1/( Time period).

Frequency of 2 us clock =1/2*10^-6 =10^6/2 =500000Hz =500 kHz.

Frequency of 0..75ms clock =1/0.75*10^-3 =10^3/0.75 =1333.33Hz =1.33kHz.

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A 5-kg ball collides inelastically head-on with a 10-kg ball, which is initially stationary. Which of the following statements i
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a. The magnitude of the change of the momentum of the 5-kg ball is equal to the magnitude of the change of momentum of the 10-kg ball.

c. The magnitude of the change of velocity the 5-kg ball experiences is greater than that of the 10-kg ball.

Explanation:

For an inelastic collision:

  • The total momentum of the system is conserved
  • The total kinetic energy of the system is not conserved

Using these facts, let's now analyze each statement given.

a. The magnitude of the change of the momentum of the 5-kg ball is equal to the magnitude of the change of momentum of the 10-kg ball.  --> TRUE. Since the total momentum is conserved, we can write:

p_1 = p_1'+p_2'

where

p_1 is the initial momentum of the 5-kg ball

p_1' is the final momentum of the 5-kg ball

p_2' is the final momentum of the 10-kg ball

The equation can be rewritten as

p_1-p_1'=p_2'

which is equivalent to

-\Delta p_1 = \Delta p_2

which means that the magnitude of the change of momentum of the two balls is the same.

b. Both balls lose all their momentum since the collision is inelastic.  --> FALSE, the 10-kg ball gains momentum, so it does not lose it.

c. The magnitude of the change of velocity the 5-kg ball experiences is greater than that of the 10-kg ball.  --> TRUE. We already said that the magnitude of the change in momentum of the two balls is the same. However, it can be written as

\Delta p = m\Delta v

where m is the mass of the ball and \Delta v its change in velocity. Therefore, the 5-kg ball (which has smaller mass) will have a larger \Delta v, so a larger change in velocity.

d. The magnitude of the change of velocity the 5-kg ball experiences is equal to that of the 10-kg ball.  --> FALSE, as we discussed in c).

e. The magnitude of the change of velocity the 5-kg ball experiences is less than that of the 10-kg ball. --> FALSE, as we discussed in c).

Learn more about change in momentum:

brainly.com/question/9484203

#LearnwithBrainly

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Answer:

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Explanation:

Given M = 3.2kg, r = 5.4m, α = –12rad/s² (it is slowing down)

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α = angular acceleration

I = moment of inertia

I = MR² for a circular hoop

Torque = 3.2×5.4×(– 12)

Torque = –207.4 Nm

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Answer:

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I think the students claim is wrong because according to Newton's First Law an object that is in motion stays in motion unless acted upon by an unbalanced force. Which makes the students claim wrong because a object doesn't require another force to keep it moving.

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Answer:

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