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qaws [65]
3 years ago
6

An arrow is used to show a force acting on an object. what information does the arrow give about the force

Physics
1 answer:
Vedmedyk [2.9K]3 years ago
6 0
The Force surrounds us and penetrates us. It flows through Jedis. May the Force be with you all.
You might be interested in
Which of these orders has the structure of the universe from the smallest to largest?
Oliga [24]

Answer:

From largest to smallest they are: Universe, galaxy, solar system, star, planet, moon and asteroid.

Explanation:

6 0
2 years ago
What is the gravitational potential energy of a two-particle system with masses 4.5 kg and 6.3 kg, if they are separated by 1.7
zepelin [54]

Answer:

7.41 x 10^-10 J

Explanation:

m = 4.5 kg

M = 6.3 kg

d = 1.7 m

The formula for the gravitational potential energy is given by

U = \frac{-GMm}{d}

Where, G is the Universal gravitational constant

G = 6.67 x 10^-11 Nm^2/kg^2

U = \frac{-6.67 \times 10^{-11}\times 6.3 \times 4.5}{1.7}

U = - 1.112 x 10^-9 J

Now the separation is tripled, d' = 3 x d = 3 x 1.7 m = 5.1 m

Let the potential energy is U'

The formula for the gravitational potential energy is given by

U' = \frac{-GMm}{d'}

Where, G is the Universal gravitational constant

G = 6.67 x 10^-11 Nm^2/kg^2

U' = \frac{-6.67 \times 10^{-11}\times 6.3 \times 4.5}{5.1}

U' = - 3.71 x 10^-10 J

the work done is equal to the change in potential energy

W = U' - U

W = - 3.71 x 10^-10 + 1.112 x 10^-9

W = 7.41 x 10^-10 J

7 0
3 years ago
A train is travelling at 15m/s. It accelerates at 3m/s² for 20 seconds. How far does the train travel in this time?
Fittoniya [83]

Answer:

Explanation:

The answer is 900m

4 0
3 years ago
Four charges of equal magnitude q = 2.16 µC are situated as shown in the diagram below. If d = 0.88 m, find the electric potenti
Triss [41]

Answer:

<em>The total potential (magnitude only) is 11045.45 V</em>

Explanation:

<u>Electric Potential </u>

The total electric potential at location A is the sum of all four individual potentials produced by the charges, including the sign since the potential is a scalar magnitude that can be computed by

\displaystyle V=\frac{kq}{r}

Where k is the Coulomb's constant, q is the charge, and r is the distance from the charge. Let's find the potential of the rightmost charge:

\displaystyle V_1=\frac{9\cdot 10^{9}\times -2.16\cdot 10^{-6}}{0.88}=-22090.91\ V

The potential of the leftmost charge is exactly the same as the above because the charges and distances are identical

V_2=-22090.91\ V

The potential of the topmost charge is almost equal to the above computed, is only different in the sign:

V_3=+22090.91\ V

The bottom charge has double distance and the same charge, thus the potential's magnitude is half the others':

\displaystyle V_4=\frac{9\cdot 10^{9}\times 2.16\cdot 10^{-6}}{1.76}=+11045.45 \ V

The total electric potential in A is

V=-22090.91\ V-22090.91\ V+22090.91\ V+11045.45 \ V

V=-11045.45 \ V

The total potential (magnitude only) is 11045.45 V

8 0
2 years ago
If the acceleration of the projective is: a = c s m/s 2 Where c is a constant that depends on the initial gas pressure behind th
Sedbober [7]

Answer:

c = 4,444.44

Explanation:

You have the following expression for the acceleration of the projectile:

a=cs   (1)

s: distance to the ground of the projectile

To find the value of the constant c you use the following formula:

v^2=v_o^2+2a \Delta s   (2)

vo: initial  velocity = 0 m/s

v: final speed = 200 m/s

Δs: distance traveled by the projectile = 3m - 1.5m = 1.5m

You replace the expression (1) into the expression (2):

v^2=2(cs)\Delta s

You do the constant c in the last equation, then you replace the values of v, s and Δs:

c=\frac{v^2}{2s\Delta s}=\frac{(200m/s)^2}{2(3m/s^2)(1.5m)}=4444.44

6 0
3 years ago
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