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Marrrta [24]
3 years ago
14

Max (15 kg) and Maya (12 kg) are ice-skating on a frozen pond. While standing at the center of the pond, Maya throws a 1.5-kg sn

owball at Max and, as a result, recoils away from Max at 2.5 m/s. With what speed did Maya throw the snowball at Max
Physics
1 answer:
pychu [463]3 years ago
4 0

Answer: The speed at which Maya threw the snowball at Max is 20m/s

Explanation:

Given that

​Mass of snowball=   1.5-kg.

Mass of Maya= 12kg

Initial  speed of Maya=2.5m/s

We use the law of conservation of  momentum to calculate the  speed of the snowball which depends on its own mass,  the mass of Maya who threw the snowball and the initial velocity at which the snowball was thrown by Maya

Ms x Us = Mm x Um

Mass of snowball  x Initial speed of Snow ball =Mass of Maya x Initial  speed of Maya

1.5kg  x Initial speed of Snow ball =12 kg x 2.5m/s

Initial speed of Snow ball=( 12 kg x 2.5m/s) /1.5kg

​ Initial speed of Snow ball  =20m/s

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3 years ago
At what displacement of a sho is the energy half kinetic and half potential? what fraction of the total energy of a sho is kinet
expeople1 [14]

As we know that KE and PE is same at a given position

so we will have as a function of position given as

KE = \frac{1}{2}m\omega^2(A^2 - x^2)

also the PE is given as function of position as

PE = \frac{1}{2}m\omega^2x^2

now it is given that

KE = PE

now we will have

\frac{1}{2}m\omega^2(A^2 - x^2) = \frac{1}{2}m\omega^2x^2

A^2 - x^2 = x^2

2x^2 = A^2

x = \frac{A}{\sqrt2}

so the position is 0.707 times of amplitude when KE and PE will be same

Part b)

KE of SHO at x = A/3

we can use the formula

KE = \frac{1}{2}m\omega^2(A^2 - x^2)

now to find the fraction of kinetic energy

f = \frac{KE}{TE} = \frac{A^2 - x^2}{A^2}

f = \frac{A^2 - (\frac{A}{3})^2}{A^2}

f_k = \frac{8}{9}

now since total energy is sum of KE and PE

so fraction of PE at the same position will be

f_{PE} = 1 - f_k

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7 0
3 years ago
Calculate the force at sea level that a boy of mass 50 kg exerts on a chair in which he is sitting.
kogti [31]

As per the question the mass of the boy is 50 kg.

The boy sits on a chair.

We are asked to calculate the force exerted by the boy on the chair at sea level.

The force exerted by boy on the chair while sitting on it is nothing else except the force of gravity of earth i.e the weight of the body .The direction of that force is vertically downward.

At sea level the acceleration due to gravity g = 9.8 m/s^2

Hence the weight of the boy w = mg  [m is the mass of the body]

we have m = 50 kg.

                             Hence w = 50 kg ×9.8 m/s^2

                                             =490 N kg m/s^2

                                              = 490 N

Here newton [N] is the unit of force.





6 0
3 years ago
Read 2 more answers
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