Answer:
Explanation:
For image formation in objective lens
object distance u = 14 +1 = 15 mm
focal length f = 14 mm .
image distance v = ?
lens formula
Putting the values
v = 210 mm .
B )
magnification = v / u
= 210 / 15
= 14
size of image = 14 x 1.1 mm
= 15.4 mm
= 15 mm approx
C )
For final image to be at infinity , image produced by objective lens must fall at the focal point of eye piece . so objective lens's distance from the image formed by objective must be equal to focal length of eye piece that is 21 mm .
21 mm is the answer .
D )
overall magnification =
D = 25 cm , f_e = focal length of eye piece
= 14 x 250 / 21
= 166.67
= 170 ( in two significant figures )
A <u><em>lead </em></u>
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<u><em>I have to use up space so ignore this part </em></u>
-- .- .-. -.- / -... .-. .- -. .. .-.. -.-- . ... - / .--. .-.. . .- ... .
The answer would be D, negative acceleration
<span>A former “supercontinent” on the Earth. In the distant past a large landmass, Pangaea, included all the present continents, which broke up and drifted apart. :)</span>
Answer:
(a)0.625s (b)1.569s
Explanation:
a.The ball reaches its maximum height when its speed = 0, or changing from positive to negative. To find out the time t for this we need to get the velocity function by taking the first derivative of the height function:
So when v(t) = 0
b. The ball land back on the ground when s(t) = 0: