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liq [111]
3 years ago
8

At the apple pan 4 burgers and 3 fries cost 26.50. 5 burgers and 5 fries cost $36.25. what is the cost for each item?

Mathematics
1 answer:
netineya [11]3 years ago
8 0
Fries are $2.50 and burgers are $4.75.

Our system of equations for this situation would be

\left \{ {{4b+3f=26.50} \atop {5b+5f=36.25}} \right.

We want the coefficients of one of the variables to be the same in order to eliminate one of them; we will make the coefficients of f the same.  To do this, multiply the top equation by 5 and the bottom equation by 3:

\left \{ {{5(4b+3f=26.50)} \atop {3(5b+5f=36.25)}} \right. 
\\
\\ \left \{ {{20b+15f=132.50} \atop {15b+15f=108.75}} \right

We subtract the bottom equation:
\left \{ {{20b+15f=132.50} \atop {-(15b+15f=108.75)}} \right. 
\\
\\ 5b = 23.75

Divide both sides by 5:
5b/5 = 23.75/5
b = 4.75

Burgers are $4.75.

Substitute this into the first equation:
4(4.75) + 3f = 26.50
19 + 3f = 26.50

Subtract 19 from both sides:
19 + 3f - 19 = 26.50 - 29
3f = 7.50

Divide both sides by 3:
3f/3 = 7.50/3
f = 2.50
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n automatic machine in a manufacturing process is operating properly if the lengths of an important subcomponent are normally di
Paraphin [41]

Answer:

0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 116 cm and a standard deviation of 5.4 cm.

This means that \mu = 116, \sigma = 5.4

Find the probability that one selected subcomponent is longer than 118 cm.

This is 1 subtracted by the pvalue of Z when X = 118. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{118 - 116}{5.4}

Z = 0.37

Z = 0.37 has a pvalue of 0.6443

1 - 0.6443 = 0.3557

0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.

8 0
3 years ago
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