Answer:
Force that acted on the body was F = 13 N
Explanation:
If once accelerated, the body covers 60 meters in 6 seconds, then its velocity is 60/6 m/s = 10 m/s
When the force was acting (for 10 seconds) the object accelerated from rest (initial velocity vi = 0) to 10 m/s (its final velocity). therefore we can use the kinematic equation for the velocity in an accelerated motion given by:

which in our case becomes;

and we can solve for the acceleration as:
a = 10/10 m/s^2 = 1 m/s^2
Therefore the force acting on the body, based on Newton's 2nd Law expression: F = m * a is:
F = 13 kg * 1 m/s^2 = 13 N
At a constant volume and
number of moles of the gas the ratio of T and P is equal to some constant.
At another set of condition, the constant is still the same. Calculations are
as follows:
T1/P1 = T2/P2
P2 = T2 x P1 / T1
P2 = 473.15 x 1.00 / 293.15
<span>P2 = 1.61 atm</span>
D. Gravitational potential