Answer:
The magnitude of the acceleration of the box is
.
Explanation:
The free body diagram of the crate is included as attachment, whose equations of equilibrium are described below:


From second equation of equilibrium we find an expression for the normal force and find the respective value:



Lastly, the acceleration experimented by the crate during pushing is cleared in the first equation of equilibrium and consequently calculated:



The magnitude of the acceleration of the box is
.
Answer:
Because of the frictional force, the net force will oppose direction of the block and be directed towards the left even tho the spring exerts no force at this point
When driving a car on the road
Im going to tell you what to do but not the result. So pay close attention: the first thing you need to do is convert miles/h to m/s. Then for the part a) <span>divide the final velocity by the initial velocity. That will give you the amount of it will take to accelerate to the final velocity.Now for the part b you </span>use the formula v=vo+at. I hope this can help you