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2 years ago

For a constant voltage, how is the resistance related to the current?

Physics

1 answer:

Aleksandr-060686 [28]2 years ago

8 0

Answer:

Resistance is inversely proportional to current, so when the resistance doubles, the current is cut in half. Resistance is directly proportional to current, so when the resistance doubles, the current is cut in half.

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Suzie (of mass 76 kg) is roller-blading down the sidewalk going 50 miles per hour. She notices a group of workers down the walkw

mel-nik [20]

Answer:

Acceleration, $a=-18.62\ m/s^2$

Explanation:

Given that,

Mass of Suzie, m = 76 kg

Initial speed of Suzie, u = 50 mph = 22.35 m/s

Finally, it stops, v = 0

Time, t = 1.2 s

Let a is the Suzie’s average acceleration. It is equal to the rate of change of velocity. Its formula is given by :

$a=\dfrac{v-u}{t}$

$a=\dfrac{0-22.35}{1.2}$

$a=-18.62\ m/s^2$

So, the average acceleration of Suzie’s is $18.62\ m/s^2$ and she is decelerating. Hence, this is the required solution.

7 0

3 years ago

FIRST ANSWER GETS BRAINLIST:

bezimeni [28]

Object A and Object B...

8 0

3 years ago

Read 2 more answers

Suppose mass and radius of the planet are half and twice that of earth's respectively. If acceleration due to gravity of the ear

stich3 [128]

Answer:

The acceleration due to gravity of that planet is, gₐ = 1.25 m/s²

Explanation:

Given that,

Mass of the planet, m = 1/2M

Radius of the planet, r = 2R

Where M and R is the mass and radius of the Earth respectively.

The acceleration due to gravity of Earth, g = 10 m/s²

The acceleration due to gravity of Earth is given by the relation,

g = GM/R²

Similarly, the acceleration due to gravity of that planet is

gₐ = Gm/r²

where G is the Universal gravitational constant

On substituting the values in the above equation

gₐ = G (1/2 M)/4 R²

= GM/8R²

= 1/8 ( 10 m/s²)

= 1.25 m/s²

Hence, the acceleration due to gravity of that planet is, gₐ = 1.25 m/s²

3 0

4 years ago

The person has an upward acceleration of 0.70 m/s^2 and is lifted from rest through a distance of 13 m. A rescue helicopter lift

Alex

Answer:

840 N

10920 J

- 10192 J

4.3 m/s

Explanation:

T = tension force in the cable in upward direction = ?

a = acceleration of the person in upward direction = 0.70 m/s²

m = mass of the person being lifted = 80 kg

Force equation for the motion of person in upward direction is given as

T - mg = ma

T = m (g + a)

T = (80) (9.8 + 0.70)

T = 840 N

d = distance traveled in upward direction = 13 m

$W_{t}$ = Work done by tension force

Work done by tension force is given as

$W_{t}$ = T d

$W_{t}$ = (840) (13)

$W_{t}$ = 10920 J

d = distance traveled in upward direction = 13 m

$W_{g}$ = Work done by person's weight

Work done by person's weight is given as

$W_{g}$ = - mg d

$W_{g}$ = - (80 x 9.8) (13)

$W_{g}$ = - 10192 J

$F_{net}$ = Net force on the person = ma = 80 x 0.70 = 56 N

v₀ = initial speed of the person = 0 m/s

v = final speed

Using work-energy theorem

$F_{net}$ d = (0.5) m (v² - v₀²)

(56) (13) = (0.5) (80) (v² - 0²)

v = 4.3 m/s

6 0

3 years ago

A horse canters away from its trainer in a straight line, moving 37 m away in 9.1 s. It then turns abruptly and gallops halfway

vesna_86 [32]

Answer:

Average velocity = 1.69 m/s

Average speed = 5.09 m/s

Explanation:

Given that

Horse cover 37 m in 9.1 sec and 18.5 m in 1.8 sec.

As we know that

Average velocity = Displacement / Total time

Average speed = Total distance / Total time

Average velocity:

Average velocity = Displacement / Total time

Total displacement = 37 - 18.5 = 18.5 m

Total time = 9.1 + 1.8 =10.9 s

Average velocity = Displacement / Total time

Average velocity = 18.5 / 10.9

Average velocity = 1.69 m/s

Average speed:

Average speed = Total distance/ Total time

Total distance = 37 + 18.5 = 55.5 m

Total time = 9.1 + 1.8 =10.9 s

Average speed = Total distance/ Total time

Average speed = 55.5 / 10.9

Average speed = 5.09 m/s

3 0

3 years ago