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Andrej [43]
2 years ago
8

A(n) __________ refers to a substance or treatment that is often used in an experiment but does not have an actual medicinal or

experimental benefit. A. Extraneous variable B. Placebo C. Confounding variable D. Independent control Please select the best answer from the choices provided A B C D.
Physics
2 answers:
dimaraw [331]2 years ago
6 0

Answer:

A __placebo (B)___ refers to a substance or treatment that is often used in an experiment but does not have an actual medicinal or experimental benefit.

Explanation:

Got it right on EDGE2022

kipiarov [429]2 years ago
3 0

Answer:

A placebo refers to a substance or treatment that is often used in an experiment but does not have an actual medicinal or experimental benefit.

Explanation:

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What evidence did astronomers use to prove jets travel in opposite directions?
mr Goodwill [35]

The evidence that astronomers use to prove jets travel in opposite direction is Spectral lines from a very fast moving ionized gases.

<h3>Who are the astronomers?</h3>

Astronomer is a person who study astronomy which is a scientific study that has to do with space, space bodies, comets, planets, stars and so on.

Therefore, The evidence that astronomers use to prove jets travel in opposite direction is Spectral lines from a very fast moving ionized gases.

Learn more about astronomers below.

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7 0
2 years ago
Read 2 more answers
A long solenoid of radius 3 cm has 1100 turns per meter. If the solenoid carries a current of 1.5 A, then calculate the magnetic
Arada [10]

Answer:

The magnetic field at the center of the solenoid is 2.1  × 10⁻³ T

Explanation:

The magnetic field B at the center of the solenoid is given by

B = μ₀ni where μ₀ = permeability of free space = 4π × 10⁻⁷H/m, n = number of turns per unit length of the solenoid = 1100 turns per meter and i = current in the solenoid = 1.5 A.

So B = μ₀ni

= 4π × 10⁻⁷H/m × 1100 × 1.5 A

= 4π × 10⁻⁷H/m × 1650 A-turns/m

= 20734.5 × 10⁻⁷T  

= 2.07345 × 10⁻³ T

≅ 2.1  × 10⁻³ T

So the magnetic field at the center of the solenoid is 2.1  × 10⁻³ T

3 0
3 years ago
I am Pushing down at a 20
s344n2d4d5 [400]

Answer:

hivhhhh

Explanation:

iiiiuuuujrurj

7 0
2 years ago
Which of the following refers to applications and technologies that are used to gather, provide access to, and analyze data and
OlgaM077 [116]

Answer:

d) business intelligence

Explanation:

 Business intelligence refers to applications and technologies that are used to gather, provide access to, and analyze data and information to support decision-making efforts. Business Intelligence uses technologies for the data analysis of business information to make strategic decision for enterprises. Common functions of business intelligence technologies include reporting, online analytical processing, analytics, data mining, process mining, complex event processing, business performance management, benchmarking, text mining, predictive analytics and prescriptive analytics.

3 0
3 years ago
A horizontal force of magnitude 46.3 n pushes a block of mass 4.14 kg across a floor where the coefficient of kinetic friction i
IrinaVladis [17]
A) Calling F the intensity of the horizontal force and d the displacement of the block across the floor, the work done by the horizontal force is equal to
W=Fd = (46.3 N)(4.25 m)=196.8 J

b) The work done by the frictional force against the motion of the block is equal to:
W_f =  -F_f d =- (\mu mg) d =-(0.609)(4.14 kg)(9.81 m/s^2)(4.25 m)=
=-105.1 J
Part of these 105.1 Joules of work becomes increase of thermal energy of the block (\Delta E_B), and part of it becomes increase of thermal energy of the floor (\Delta E_F). We already know the increase in thermal energy of the block (38.2 J), so we can find the increase in thermal energy of the floor:
\Delta E_F = 105.1 J - \Delta E_B = 105.1 J-38.2 J=66.9 J

c) The net work done on the block is the work done by the horizontal force F minus the work done by the frictional force (the frictional force acts against the motion, so we must take it with a negative sign):
W_{net}=W-W_f=196.8 J-105.1 J=91.7 J
For the work-energy theorem, the work done on the block is equal to its increase of kinetic energy:
W_{net} = \Delta K
So, we have \Delta K=+91.7 J


5 0
3 years ago
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