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oee [108]
2 years ago
7

Why did the ball not reach its original height after bouncing once

Physics
2 answers:
Nataly [62]2 years ago
6 0

Answer:

it slows down after every bounce

gizmo_the_mogwai [7]2 years ago
3 0

huh.... what.... i...

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In a series circuit, when batteries are added to the circuit the voltage will _____ and the current will _____.
Eva8 [605]

Answer: voltage, explode is the answers

Explanation:

Bc of the device for each  server

5 0
3 years ago
Two 8.0 Ω lightbulbs are connected in a 12 V parallel circuit. What is the power of both glowing bulbs?
kati45 [8]

Answer:

96w

Explanation:

p=Iv..where v=12 and I=8.0

8 0
2 years ago
The distance between adjacent nodes in a standing wave pattern in a length of string is 25.0 cm:A. What is the wavelength of wav
mina [271]

A) 50 cm

B) 10000 cm/s

Explanation

Step 1

A)

If you know the distance between nodes and antinodes then use this equation:

\begin{gathered} \frac{\lambda}{2}=D \\ \text{where}\lambda\text{ is the wavelength} \\ D\text{ is the distance betw}een\text{ nodes} \end{gathered}

then, let

D=\text{ 25 cm }

now, replace to find the wavelength

\begin{gathered} \frac{\lambda}{2}=25 \\ \text{Multiply both sides by 2} \\ \frac{\lambda}{2}\cdot2=25\cdot2 \\ \lambda=50\text{ Cm} \end{gathered}

so, the wavelength is

A) 50 cm

Step 2

The speed of a wave can be found using the equation

v=\lambda f

or velocity = wavelength x frequency,

then,let

\begin{gathered} \lambda=50\text{ cm} \\ f=200\text{ Hz} \end{gathered}

replace and evaluate

\begin{gathered} v=\lambda f \\ v=50\text{ cm }\cdot200\text{ HZ} \\ v=10000\text{ }\frac{\text{cm}}{s} \end{gathered}

so

B) 10000 cm/s

I hope this helps you

6 0
1 year ago
Inertia is the resistance to change in motion do inertia depends solely on what?
Y_Kistochka [10]
Resistance is what Inertia goes to.....
8 0
3 years ago
According to the Big Bang Theory, the density and temperature of the Universe is ___________ now than in the past.
34kurt

Answer:

According to the Big Bang Theory, the density and temperature of the Universe is <u>lower</u> now than in the past.

<em>Hope</em><em> this</em><em> answer</em><em> correct</em><em> </em><em>:</em><em>)</em>

5 0
3 years ago
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