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miss Akunina [59]
3 years ago
5

A car travels at 35.0 mi/hr. How far has it gone in 2455 seconds?

Chemistry
1 answer:
Vika [28.1K]3 years ago
5 0

Answer:

<h3>The answer is 23.8 miles</h3>

Explanation:

The distance covered by an object given it's velocity and time taken can be found by using the formula

<h3>distance = velocity × time</h3>

From the question

velocity = 35.0 mi/hr

time = 2455 s = 0.68 hr

We have

distance = 35 × 0.68

We have the final answer as

<h3>23.8 miles</h3>

Hope this helps you

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Setler [38]

Answer:

8.5155g NH3

Explanation:

the molar mass of NH3​ is 17.031 g/mol

0.5 mol NH3 x 17.031 gNH3/1 mol NH3 = 8.5155g NH3

4 0
3 years ago
What is a non-example for an Electric circuit?
Mademuasel [1]

Answer:

Impressionist paintings are a non-example of electric circuits.

Explanation:

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4 0
2 years ago
Read 2 more answers
What volume in liters of carbon monoxide will be required to produce 18.9 L of nitrogen in the reaction below
mina [271]

Answer:

37.8 L OF CARBON MONOXIDE IS REQUIRED TO PRODUCE 18.9 L OF NITROGEN.

Explanation:

Equation for the reaction:

2 CO + 2 NO ------> N2 + 2 CO2

2 moles of carbon monoxide reacts with 2 moles of NO to form 1 mole of nitrogen

At standard temperature and pressure, 1 mole of a gas contains 22.4 dm3 volume.

So therefore, we can say:

2 * 22.4 L of CO produces  22.4 L of N2

44.8 L of CO produces 22.4 L of N2

Since, 18.9 L of Nitrogen is produced, the volume of CO needed is:

44.8 L of CO = 22.4 L of N

x L = 18.9 L

x L = 18.9 * 44.8 / 22.4

x L = 18.9 * 2

x = 37.8 L

The volume of Carbon monoxide required to produce 18.9 L of N2 is 37.8 L

8 0
3 years ago
If the system 3H2(g) N2(g) 2NH3(g) is at equilibrium and more N2 is added, a net reaction that consumes some of the added N2 wil
kondor19780726 [428]

Group Starts True

A rightward change in equilibrium.

The concentration of gases = [H2] will decrease, [N2] will increase, [NH3] will increase when the new equilibrium is reached.

Additional heat is produced.

The forward and backward reactions' rates quicken in the new equilibrium.

The equilibrium constant decreases as more heat is released.

the exothermic nature of the process.

The equilibrium constant would not have changed if the temperature had remained constant.

Learn more about Equilibrium here

brainly.com/question/13414142

#SPJ4

8 0
2 years ago
Please help me on this I’ll give 30 points
Rufina [12.5K]

Answer:

                     1. 10.66 moles of Al

                     2.  2.5 moles of Al₂O₃

                     3. 143.87 g of SO₂

Explanation:

                    The balance chemical equation is as follow,

                                      4 Al + 3 O₂ → 2 Al₂O₃

<h3>1.</h3>

According to balance chemical equation,

                       3 moles of O₂ required  =  4 moles of Al

So,

                     8 moles of O₂ will require  =  X moles of Al

Solving for X,

                      X =  8 mol × 4 mol / 3 mol

                      X =  10.66 moles of Al

<h3>2.</h3>

According to balance chemical equation,

                       4 moles of Al produced  =  2 moles of Al₂O₃

So,

                     5 moles of Al will produce  =  X moles of Al₂O₃

Solving for X,

                      X =  5 mol × 2 mol / 4 mol

                      X =  2.5 moles of Al₂O₃

<h3>3.</h3>

The balance chemical equation for the oxidation of carbon disulfide is as follow;

                                CS₂ + 3 O₂ → CO₂ + 2 SO₂

Step 1: <u>Calculate Moles of CS₂ as;</u>

                  Moles  =  Mass / M.Mass

                  Moles  =  85.5 g / 76.14 g/mol

                  Moles  =  1.12 moles of CS₂

Step 2: <u>Find out moles of SO₂ as;</u>

According to balance chemical equation,

                       1 mole of CS₂ produced  =  2 moles of SO₂

So,

                     1.12 moles of CS₂ will produce  =  X moles of SO₂

Solving for X,

                      X =  1.12 mol × 2 mol / 1 mol

                      X =  2.24 moles of SO₂

Step 3: <u>Calculate Mass of SO₂ as;</u>

                  Mass  =  Moles × M.Mass

                  Mass  =  2.24 mol × 64.06 g/mol

                  Mass  =  143.87 g of SO₂

4 0
3 years ago
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