All categories

3 years ago

Solution made up of a

Chemistry

1 answer:

Vadim26 [7]3 years ago

5 0

Answer:

solute and solvent

Explanation:

Because solutes dissolves in solvent to form a solution

You might be interested in

How are photosynthesis and cellular respiration related?

Vladimir79 [104]

Answer:

B part is the correct answer

4 0

3 years ago

Chloroform has a density of 1.5 g/ml. What the mass of 10.0 ml of Chloroform?

anzhelika [568]

Volume=10ml
Density=1.5g/ml

$\boxed{\sf Density=\dfrac{Mass}{Volume}}$

$\\ \sf\longmapsto Mass=Density\times Volume$

$\\ \sf\longmapsto Mass=1.5(10)$

$\\ \sf\longmapsto Mass=15g$

6 0

3 years ago

Some athletes have as little as 3.0% body fat. If such a person has body mass of 65 kg,how many pounds of body fat does tha

coldgirl [10]

They would have 5%:::::)

8 0

4 years ago

HELP ASAP!!! Which part of a comet exists even when it is very far away from the Sun?

Afina-wow [57]

The solid portion of a comet—the only portion that exists when the comet is far from the Sun.

3 0

3 years ago

Read 2 more answers

Perform the calculation and report the answer using the proper number of significant figures. Make sure the answer is rounded co

shusha [124]

This question is an incomplete question, here is a complete question.

Perform the following calculation. Report the answer using the proper number of significant figures.

$\frac{1.012\times 10^{-3}J}{(0.025456g)\times (298.3682-298.3567)K}=?$

Answer : The answer will be, $3.46J/g.K$

Explanation :

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

The rule apply for the multiplication and division is :

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

The rule apply for the addition and subtraction is :

The least precise number present after the decimal point determines the number of significant figures in the answer.

The given expression is,

$\frac{1.012\times 10^{-3}J}{(0.025456g)\times (298.3682-298.3567)K}$

$\frac{1.012\times 10^{-3}J}{(0.025456g)\times (0.0115)K}$

$\Rightarrow 3.4569J/g.K$

In the given expression, 1.012 has 4 significant figures, 0.025456 has 5 significant figures and 0.0115 has 3 significant figures. From this we conclude that 3 is the least significant figures in this problem. So, the answer should be in 3 significant figures.

Thus, the answer will be $3.46J/g.K$

7 0

3 years ago