Organic: sugar
inorganic: salt
Answer:
B) PO2
Explanation:
first solve empirical formula
50%of P and 50%of O
- divide each by molecular mass
P. O
50/32. 50/16
1.5. 3.0
- divide both by the smallest
1.5/1.5. 3.0/1.5
1. :. 2
Empirical formula=PO2
Molecular formula=PO2
(PO2)n= 64
(32+(16×2)=64
(32+32)n=64
64n=64
n= 1
Answer:
29.3 g HClO₄
Explanation:
We have 39.1 grams of 74.9 wt% aqueous perchloric acid solution, that is, there are 74.9 grams of perchloric acid in 100 grams of perchloric acid solution. The mass, in grams, of perchloric acid contained in 39.1 grams of perchloric acid solution is:
39.1 g Solution × (74.9 g HClO₄/100 g Solution) = 29.3 g HClO₄
Answer:
it is option b
Explanation:
this is because neutralisation reaction takes place only between a base and an acid.
now, in OPTION A it is a neutral and base
OPTIONB it is acid and base
OPTION C both are base
OPTION D IT IS NOT POSSIBLE
