Answer:
(a) -1.18 m/s
(b) 0.84 m/s
Explanation:
(a)
The total linear momentum before the lumberjack begins to move is zero because all parts of the system are at res
From the law of conservation of momentum
m1v1+m2v2=0 hence m1v1=-m2v2 where m1 is mass of lumberjack, v1 is velocity of lumberjeck, m2 is mass of floating log, v2 is velocity of the floating log.
Substituting M1 for 103 Kg, V1 for 2.93 m/s, M2 for 255 Kg into the above equation we obtain
103Kg*2.93 m/s=-255Kg*V2
V2=-(103 kg*2.93 m/s)/255=-1.183490196 m/s
Hence V2=-1.18 m/s
(b)
For the second log
V(M1+M2)=m1v1 where V is the common velocity
V(103 Kg+255 Kg)=103 Kg*2.93 m/s
V=(103 Kg*2.93 m/s)/(103 Kg+255 Kg)=0.842988827 m/s
V=0.84 m/s
Answer:
Required horizontal distance is 0.9279 meters
Explanation:
The situation is represented in the attached figure
The horizontal distance can be seen to be equal to
In the upper triangle we have
Now the angle can be calculated using Snell's law
By snell's Law we have
Since light comes from air thus
Light enter's the water thus we have
Applying values we calculate as
Now in the attached figure we have
Solving for we get
thus the required horizontal distance is
It's really difficult to make out the circuit above. Quite frankly, your
question leaves me to wonder how far 'above' it may be.
The best I can do will be to try and fabricate an answer based on the
information given in the text of the question, augmented only by my own
training, chutzpah, and life experiences.
If the circuit ... wherever it is ... consists entirely of the single 3-ohm
resistance and no other components, and the current through the
resistance is 10 Amperes, then
Voltage = (Current) x (resistance) = 30 volts .