Please please help me out!!!!!
1 answer:
Answer:
see explanation
Step-by-step explanation:
By the rational root theorem, any rational roots of f(x) are expressible in the form
for integers p and q
with p a divisor of the constant term 6 and q a divisor of the leading coefficient 1.
The possibilities are ± 1, ± 2, ± 3, ± 6
Since the lead coefficient is 1 dividing by that number doesn't change a thing.
Thus the possible rational roots are
= - 6, - 3, - 2, -1, 1, 2, 3, 6
You might be interested in
1. No answer ( may be due to incorrect question)
2. x = -3
y = 4
3. x= 4
y = 2
4.x = -63/40
y= -19/20
Step 1
Multiply equation 1 by the coefficient of x in equation 2
Multiply equation 2 by the coefficient of x I'm equation 1
(after completing this step you will derive equation 3 and 4 )
Step 2
Subtract equation 4 from equation 3
Step 3
Divide both sides of the equation by the coefficient of y
Step 4
substitute your value for y in equation 1 or 2
(after this you will derive the values of x)
Note : This method is for the Elimination of x
I hope it helps
