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3 years ago

Describe the solutions of 2-5>n in words

1 answer:

5 0

$2-5\ \textgreater \ n \ \textgreater \ Switch\;sides \ \textgreater \ n\ \textless \ 2-5 \ \textgreater \ Simplify \ \textgreater \ 2-5 \ \textgreater \ -3$

$n\ \textless \ -3$

Hope this helps!

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At a store, 2 gallons of milk cost $6. Which is the value of the ratio of dollars to gallons of milk?

Nataliya [291]

1 gallon = $3 so the ratio would be 1:3 where 1 would represent the gallon and 3 the price

3 0

3 years ago

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I will mark you the brainiest for the correct answer, please be correct, Have a good day and take care, thanks. ( VIEW THE IMAGE

makkiz [27]

Mistake in Line 2 : Was in the determining the values for a ,b,c

Mistake in Line 4 : Not taking the square roots of both sides.

Step-by-step explanation:

${a}^{2} + {b}^{2} = {c}^{2}$

First Mistake : Line 2

$a = x \\ b = 6 \\ c = 10$

Second Mistake : Line 4

$136 = {x}^{2} \\ not \\ 136 = x$

Correct Solution :

${x}^{2} + {6}^{2} = {10}^{2} \\ {x}^{2} = {10}^{2} - {6}^{2} \\ {x}^{2} = 100 - 36 \\$

${x}^{2} = 64 \\ \sqrt{ {x}^{2} } = \sqrt{64} \\ x = 6$

3 0

3 years ago

How do you find the point slope form? (given 2 points)

belka [17]

Point-slope form is written as : y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point.

The slope (m) is found by the change in Y over the change in X

Slope = (y2 - y1) / (x2 - x1)

You can use either given point for x1 and y1 so you would calculate the slope and replace m with the slope, then replace x1 and y1 in the equation with their value.

8 0

3 years ago

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A line passes through the points (–5, 2) and (10, –1). Which is the equation of the line?

LenKa [72]

We have y - 2 = m(x + 5), where m = (-1 - 2)/(10 + 5) = -3/15 = -1/5;
Then y - 2 = (-1/5)(x + 5);
5y - 10 = (-1)(x + 5);
5y - 10 = -x - 5;
x + 5y - 5 = 0 is the equation of the line.

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3 years ago

How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the

miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

$\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}$

___

$\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}$

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$\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}$

Neither solution makes any denominator be zero, so both are good solutions.

8 0

3 years ago