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Dima020 [189]
3 years ago
6

A solution contains 22.4 g glucose (C6H12O6 ) dissolved in 0.500 L of water. What is the molality of the solution

Chemistry
1 answer:
Shalnov [3]3 years ago
8 0

Answer:

Molality is 0.25 m

Explanation:

Molality → Moles of solute / kg of solvent

We need the moles of solute → 0.124 moles

22.4 g . 1 mol / 180 g = 0.124 moles

We need the mass of solvent in kg. We determine the mass of solvent with density.

Density = Mass / Volume

Mass = Density . volume → 1 g/mL . 500 mL = 500 g

If we convert the mass in g to kg → 500 g . 1kg / 1000 g = 0.5 kg

In conclussion, molality → 0.124 mol / 0.5 kg = 0.25 m

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Moles of glucose = Molarity x volume solution 
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Hope this helps, have a great day ahead!
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IRINA_888 [86]
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