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exis [7]
3 years ago
9

CN- is a Bronsted - Lowry base. What will this substance form when it accepts a proton?

Chemistry
1 answer:
sergejj [24]3 years ago
8 0
It will form HCN Hydrogen Cyanide.
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One of the hopes for solving the world's energy problem is
lions [1.4K]

Answer:

2.803013439419911 × 10⁻¹² J

Explanation:

Mass defect = mass of reactant - mass of product

(2.0140 + 3.01605) - (4.002603 + 1.008665)

5.03005 - 5.011268 = 0.018782 amu

mass in Kg = mass (amu) × 1.66053892173 × 10⁻²⁷ kg

mass in kg = 0.018782 × 1.66053892173 × 10⁻²⁷ = 3.1188242027932 × 10⁻²⁹kg

E = Δm c² where c is the speed of light = 2.9979 × 10⁸m/s

E = 3.1188242027932 × 10⁻²⁹kg × (2.9979 × 10⁸m/s)² = 2.803013439419911 × 10⁻¹² J

6 0
3 years ago
Besides their shape, how does a 2p orbital differ from a 3d orbital? chegg.
Blababa [14]

Answer:

The 3p orbitals have the same general shape and are larger than 2p orbitals, but they differ in the number of nodes. You have probably noticed that the total number of nodes in an orbital is equal to n−1 , where n is the principal quantum number. Thus, a 2p orbital has 1 node, and a 3p orbital has 2 nodes.

5 0
2 years ago
a. Calculate the pH of a solution that has [H3O+]= 4.3 x 10-5 M. b. Is the solution acidic or basic? How do you know?
Luda [366]

Answer:

* pH=4.37

* The solution is acidic since the pH is below 7.

Explanation:

Hello,

In this case, we can mathematically define the pH by:

pH=-log([H_3O^+])

Thus, for the given hydronium concentration we simply compute the pH:

pH=-log(4.3x10^{-5})=4.37

Thereby, we conclude the solution is acidic due to the fact that the pH is below 7 which is the neutral point and above it the solutions are basic.

Regards.

3 0
3 years ago
Question 10
zepelin [54]
Because the ring is hollow
3 0
3 years ago
A generic gas, x, is placed in a sealed glass jar and decomposes to form gaseous y and solid z. 2x(g)â½ââây(g)+z(s) how are thes
Elan Coil [88]
The chemical equation given is:

<span>2x(g) ⇄ y(g)+z(s)</span>

Answer: the higher the amount of x(g) the more the forward reacton will occur and the higher the amounts of  products y(g) and z(s) will be obtained at equilibrium.

Justification:

As Le Chatellier's priciple states, any change in a system in equilibrium will be compensated to restablish the equilibrium.

The higher the amount, and so the concentration, of X(g), the more the forward reaction will proceed to deal witht he high concentration of X(g), leading to an increase on the concentration of the products y(g) and z (s).
3 0
3 years ago
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