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il63 [147K]
3 years ago
15

The fluorocarbon compound c2cl3f3 has a normal boiling point of 47.6°c. the specific heats of c2cl3f3(l) and c2cl3f3(g) are 0.91

j/g·k and 0.67 j/g·k, respectively. the heat of vaporization for the compound is 27.49 kj/mol. calculate the heat required to convert 36.0 g of c2cl3f3 from a liquid at 10.00°c to a gas at 108.00°c.
Chemistry
1 answer:
myrzilka [38]3 years ago
7 0
<span>To raise the liquid temperature to the point of boiling take 1231.776 joules of energy. To convert to a gas takes 5320.645 joules. To raise to 108 degrees Celsius takes 1456.848 joules. Total amount of energy needed (as heat) equals 8009.269 joules or 8.009 kj.</span>
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2. Calculate the joules of energy required to heat 454.3g of water<br> frum 5.4°C to 98.6°C.
Tasya [4]

Answer:

176984.38J

Explanation:

E = mC∆T

Where E is the energy in joules

M is the mass of water

C is the specific heat capacity of water =4.184J/g°C

It is known that it will take 4.184J of energy to change the temperature of water by one degree Celsius.

∆T = 98.6°c - 5.4°c

= 93.2°c

∆H = 454.3g × 4.18J/g°C × 93.2°c

= 176984.3768

176984.38J

7 0
3 years ago
Why can't scientists simply use carbon-12 (12C) do determine
Alex

Answer:

carbon-12 is not radioactive

Explanation:

The measurement of the age of dead carbon based life forms requires the use of a radioactive isotope hence it is often referred to as radiocarbon dating.

Carbon-12 and Carbon-14 occur together in living things.The half life of Carbon-14 is about 5670 years.

Hence, since Carbon-12 is not radioactive, it can not be used to measure the age of dead carbon based materials.

8 0
3 years ago
Advantages of anthropology​
Elena L [17]

Answer:

I would use it for a while speed is the

3 0
3 years ago
Please help me ..If you don't have a question or something to say just comment don't steal my points . It's not fair. Here are t
astra-53 [7]

1.

1.20 \: mol \times  \frac{6.02 \times  {10}^{23} }{1 \: mol}  = 7.224 \times  {10}^{23} atoms

2.

9.25 \times  {10}^{25 \:} molecules \times  \frac{1 \: mol}{6.02 \times  {10}^{23} }

= 153.654485 \: moles

3.

molar mass = 3(24.31) + 127.60 + 5(32.07)

molar mass = 360.88 g

4.

molar mass = 3(58.93) + 2(30.97) + 8(16.00)

molar mass = 366.73 g

5.

molar mass = 98.09

125 \: g \times  \frac{1 \: mol}{98.09 \: g}  = 1.274339892 \: moles

//

I'm too lazy to do the rest but you should get a general idea of how to do it.

Also, round as you wish!

3 0
2 years ago
Read 2 more answers
The phase change h2(g) → h2(s) is called ________, and the enthalpy change, δh, for this phase change has a ________ sign.
Tpy6a [65]
The phase change H₂(g) → H₂(s) is called deposition, and the enthalpy change, ΔH, for this phase change has a negative (-) sign.
Deposition<span> is a </span>thermodynamic process<span> in which </span>gas<span> transforms into </span>solid<span> without passing through the </span>liquid phase<span>. Example is formin snow in clouds directly from water vapor. In deposition energy is released.</span>

7 0
3 years ago
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