Answer:
Gamma
Explanation:
I'm not sure how to do it without calculations but:
E=hv
7*10^7 J/mol=6.626*10^34 Js * v
v=1*10^41
Gamma rays.
More here: https://www.hasd.org/faculty/AndrewSchweitzer/spectroscopy.pdf
Explanation:
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The signs of ΔS° and ΔH° will be negative.
A combustion reaction is a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat.
Combustion reactions must involve O2 as one reactant.
Consider the combustion of butane gas:
C₄H₁₀(g ) + 13/2O₂(g) → 4CO₂(g) + 5H₂O(g)
4 + 13/2 4 + 5
10.5 mol -------------> 9 mol
As the number of moles decreases entropy will decrease
so ΔS° = negative
since this example for combustion reaction heat is released (exothermic)
so ΔH° = negative.
Learn more about ΔS° here:
brainly.com/question/3784176
#SPJ4
Can you show me the atoms please? I would be able to help.