Help on questión 13 please

I need help with this problem

Andrei [34K]

Answer:

-20d^3 + 55d + 35.

Step-by-step explanation:

-4d(5d^2 - 12) + 7(d + 5)

= -20d^3 + 48d + 7d + 35

= -20d^3 + 55d + 35.

3 0

3 years ago

PLZZ ANSWERPLZ PZLZZZZ

LenKa [72]

The answer is 2 and 1/8

8 0

3 years ago

The percent of fat calories that a person in America consumes each day is normally distributed with a mean of about 36 and a sta

maksim [4K]

Answer:

a) 1

b) X = 34.313

c) 4.79*10⁻⁷

d) 36.67449

Step-by-step explanation:

a) Given data

Mean: μ = 37

n = 16

Standard deviation: σ = 10

For a group of 16 individuals, probability that the average percent of fat calories consumed is more than 5 is given by

P(x ≥ 5)

Changing into standard normal variate

P(z ≥ (5 - 36)/(10/√16)) = P(z ≥ -12.4)

P(z ≥ -12.4) = 1 - P(z < -12.4) = 1 - 1.3*10⁻³⁵ ≈ 1

From excel NORM.ES.DIST(-12.4, TRUE): P(z < -12.4) = 1.3*10⁻³⁵

b) First quartile for the average percent of fat calories

Finding the value of Z at P = 0.25

Z(P = 0.25) = -0.67449 ( From Excel =NORM.S.INV(0.25))

Z = (X - μ)/(σ/√n)

⇒ -0.67449 = (X - 36)/(10/√16)

⇒ X = 34.313

c) Given

n = 100

P(85 < x < 1250)

Z₁ = (X₁ - μ)/σ ⇒ Z₁ =(85 - 36)/10 = 4.9

Z₂ = (X₂ - μ)/σ ⇒ Z₂ =(1250 - 36)/10 = 121.4

P(4.9 < Z < 121.4) = P(Z < 121.4) - P(Z ≤ 4.9) = = 4.79*10⁻⁷

d) n = 100

Third quartile for the average percent of fat calories

Finding the value of Z at P = 0.75

Z(P = 0.75) = 0.67449 ( From Excel =NORM.S.INV(0.75))

Z = (X - μ)/(σ/√n)

⇒ 0.67449 = (X - 36)/(10/√100)

⇒ X = 36.67449

5 0

4 years ago

Read 2 more answers

What is the equation of the line that is perpendicular to y, =, 1 over 3 x, 4. And contains the point negative 2, negative 5,?.

Anit [1.1K]

The equation of the line is, $\rm y = 3x + 1$ .

Given that,

The equation of the line is,

$\rm y = \dfrac{1}{3} x+4\\$

And contains the point (-2, -5).

We have to determine,

What is the equation of the line that is perpendicular to the given line?

According to the question,

The equation of the line is,

$\rm = \dfrac{1}{3}x + 4\\$

On comparing with the standard equation of the line y = mx +c.

The slope of the line $m_1$ is 1/3.

When two lines are perpendicular the relation between these slopes is,

$\rm m_1\times m_1 = {-1}\\\\\dfrac{-1}{3} \times m_2 = -1\\\\-1 \times m_2 = -1 \times 3\\\\-m_2 = -3\\\\m_2 = 3$

And line contains the point (-2, -5).

Then,

$\rm y = mx +c \\\\-5 = 3 (-2) + c\\\\-5 = -6+c \\\\c = 6-5 \\\\c = 1$

Therefore,

The equation of the line that is perpendicular to the given line and contains the point (-2, -5) is,

$\rm y = mx +c \\\\y = 3x +1$

Hence, The required equation of the line is, $\rm y = 3x + 1$ .

For more details refer to the link given below.

brainly.com/question/14388443

7 0

3 years ago

Four less than the product of 11 and Victor's height

3241004551 [841]

Can I have brainliest? and I’m not sure what question you are asking !! 11-4= 7

7 0

3 years ago

Read 2 more answers