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emmasim [6.3K]
3 years ago
12

Help on questión 13 please

Mathematics
1 answer:
elena-s [515]3 years ago
4 0
So make a picture. so i could help u more
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Ms. Drohan's dog weighs 11 pounds 8 ounces. Ms. Granahan's dog weighs 245 ounces. Whose dog weighs more? A.
mash [69]

Answer: B . Ms. Granahan's dog weighs more

Step-by-step explanation:

1 pound = 16 ounces

11 pounds x 16 ounces = 176 ounces

176 + 8 ounces = 184 ounces

therefore , Ms. Drohan's dog weighs 185 ounces

B is the answer.

7 0
3 years ago
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If the rate of inflation is3.7% per year the future price p(t)(in dollars) of a certain item can be modeled by the following exp
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Current price : 600
Price 10 years from today :
P (10)=600×(1.037)^(10)=862.86
7 0
3 years ago
Garrett buys lunch for himself and his friend. He buys 2 sandwiches, 2 fries, and 2 malts. How much did Garrett spend on lunch?
Yanka [14]

Answer:

How much is each sandwich, fry, and malt? I can out the answer in the comments, I just need more info.

8 0
3 years ago
a bird flies 25 miles Due West then turns due south and flies for another 15 miles and lands how far is the bird from its starti
Crazy boy [7]
Check the picture below.

4 0
3 years ago
In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ )  = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ =  0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

6 0
2 years ago
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