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3 years ago

Is it possible for two different atoms of carbon to have different numbers of neutrons in their nuclei? Explain.

Physics

1 answer:

bezimeni [28]3 years ago

4 0

Answer:

Yes , it is possible for two different atoms of carbon to have different numbers of neutrons in their nuclei .

Explanation:

Isotopes -

Atoms of the element with same number of the electrons and protons , but differ in the number of neutrons , are called as the isotopes .

The isotopes of the element have the same number of protons and electrons , hence have the same chemical and physical properties .

Many isotopes occurs naturally .

In case of Carbon ,

Carbon too have isotopes ,

i.e.

Carbon - 13 and Carbon - 14

carbon - 13 , have seven neutrons

Carbon - 14 , have eight neutrons .

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A 0.10 kg mass is oscillating at a small angle from a light string of length 0.10 m.

cupoosta [38]

Answer:

tough

Explanation:

5 0

2 years ago

With what force will a car hit a tree if the car has a mass of 3,415 kg and it is accelerating at

weeeeeb [17]

Answer:

$F= 17,075\ N$

Explanation:

When the car is under an accelerating force and hits a tree, the instant force received by the tree is the same force that is accelerating the car.

The accelerating force can be calculated using Newton's second law:

$F=m\cdot a$

Where m is the mass of the car and a is the acceleration.

$F=3,415\ kg\cdot 5\ m/s^2$

$\boxed{F= 17,075\ N}$

3 0

3 years ago

How can you tell if something has a lot of kinetic energy? How can you tell if something only has a little bit of kinetic energy

dezoksy [38]

Based on the equation KE = 1/2(m)(v^2), Kinetic Energy can be measured based on velocity. If an object has a large velocity, it have a larger kinetic energy than if the velocity is small.

Hope this helps.

If this helped you, please vote me as brainliest!

3 0

3 years ago

Collar P slides outward at a constant relative speed along rod AB, which rotates counterclockwise with a constant angular veloci

diamong [38]

Answer:

a= 23.65 ft/s²

Explanation:

given

r= 14.34m

ω=3.65rad/s

Ф=Ф₀ + ωt

t = Ф - Ф₀/ω

= (98-0)× $\frac{\pi}{180}$ /3.65

98°= 1.71042 rad

1.7104/3.65

t= 0.47 s

r₁(not given)

assuming r₁ =20 in

r₁ = r₀ + ut(uniform motion)

u = r₁ - r₀/t

r₀ = 14.34 in= 1.195 ft

r₁ = 20 in = 1.67 ft

= (1.667 - 1.195)/0.47

0.472/0.47

u= 1.00ft/s

acceleration at collar p

a=rω²

= 1.67 × 3.65²

a = 22.25ft/s²

acceleration of collar p related to the rod = 0

coriolis acceleration = 2ωu

= 2× 3.65×1 = 7.3 ft/s²

acceleration of collar p

= 22.5j + 0 + 7.3i

√(22.5² + 7.3²)

the magnitude of the acceleration of the collar P just as it reaches B in ft/s²

a= 23.65 ft/s²

4 0

3 years ago

Find electric field at point p which is a distance l away from the both +q and -q

denis-greek [22]

Answer:

$\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }$

Explanation:

As given point p is equidistant from both the charges

It must be in the middle of both the charges

Assuming all 3 points lie on the same line

Electric Field due a charge q at a point ,distance r away

$=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{r^{2} }$

Where

q is the charge
r is the distance
$E$ is the permittivity of medium

Let electric field due to charge q be F1 and -q be F2

I is the distance of P from q and also from charge -q

⇒

F1 $=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }$

F2 $=\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }$

⇒

F1+F2= $\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }$

8 0

3 years ago