Answer:
Explanation:
Call the bike on the right A
Call the bike on the left B
The car begins it's time when it passes A
4 minutes later, it passes B.
But B has moved in 4 minutes and that is the key to the problem.
How far has B moved.
t = 4 minutes = 4/60 hours = 1/15 of an hour.
d = ?
rate = 30 km / hr
d = r * t
d = 30 km/hr * 1/15 hours = 2 km
The distance between the bikes is 5 km.
So the car has traveled 5 - 2 = 3 km
d = 3 km
r = ?
t = 4 minutes = 1/15 hour
r = d/t = 3/(1/15)= 3 / 0.066666666 = 45 km/hr.
1. earth
2. solar system
3. milky way galaxy
4. local group of galaxies
5. universe
<span>In the </span>natural logarithm<span> format or in equivalent notation (see: </span>logarithm) as:
base<span> e</span><span> assumed, is called the </span>Planck entropy<span>, </span>Boltzmann entropy<span>, Boltzmann entropy formula, or </span>Boltzmann-Planck entropy formula<span>, a </span>statistical mechanics<span>, </span><span> </span>S<span> is the </span>entropy<span> of an </span>ideal gas system<span>, </span>k<span> is the </span>Boltzmann constant<span> (ideal </span>gas constant R<span> divided by </span>Avogadro's number N<span>), and </span>W<span>, from the German Wahrscheinlichkeit (var-SHINE-leash-kite), meaning probability, often referred to as </span>multiplicity<span> (in English), is the number of “</span>states<span>” (often modeled as quantum states), or "complexions", the </span>particles<span> or </span>entities<span> of the system can be found in according to the various </span>energies<span> with which they may each be assigned; wherein the particles of the system are assumed to have uncorrelated velocities and thus abide by the </span>Boltzmann chaos assumption<span>.
I hope this helps. </span>
v2 = ?
m1 = 10kg
m2 = 70kg
v1 = 4m/s
E1 = E2
E1 = 1/2 * m1 * v1^2 = 1/2 * 10kg * 4m/s^2 = 80J
E2 = 1/2 * m2 * v2^2 = 80 J
v2 = √(E2/(2 * m2)) = √(80J/(2 * 70kg)) = about 0.76m/s
