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3 years ago

8

A large electrical device is plugged into a 240-volt outlet and has a resistance of 160 ohms. How much power does the device use

.
A.38,000 watts
B.1.5 watts
C.360 watts
D.100 watts
E.0.67 watts

2 answers:

Darya [45]3 years ago

6 0

The answer is simple 360 watts

lubasha [3.4K]3 years ago

5 0

Yur answer is c.360 watts

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In designing circular rides for amusement parks, mechanical engineers must consider how small variations in certain parameters c

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Answer:

Part a)

$dF = -\frac{mv^2}{r^2} dr$

Part b)

$dF = \frac{2mvdv}{r}$

Part c)

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Explanation:

Part a)

As we know that force on the passenger while moving in circle is given as

$F = \frac{mv^2}{r}$

now variation in force is given as

$dF = -\frac{mv^2}{r^2} dr$

here speed is constant

Part b)

Now if the variation in force is required such that r is constant then we will have

$F = \frac{mv^2}{r}$

so we have

$dF = \frac{2mvdv}{r}$

Part c)

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$dT = - \frac{2\pi r}{v^2} dv$

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3 years ago

If you know the amount of air pressure exerted on a tabletop, how can you calculate the force exerted on the tabletop? Multiply

babymother [125]

Answer:

Multiply the air pressure by the area of the tabletop.

Explanation:

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$p=\frac{F}{A}\\p\cdot A=\frac{F}{A}\cdot A\\pA=F$

So, the correct answer is:

The force exerted on the tabletop can be found by multiplying the air pressure by the area of the tabletop.

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(8.98755 x 10⁹ N-m²/C²) x (1.602 x 10⁻¹⁹ C)² / D²

In order for the bottom one to just exactly hold the top one up at a distance 'D', the repelling force has to be exactly equal to the weight of the upper electron.

8.926 x 10⁻³⁰ N = (8.98755 x 10⁹ N-m²/C²)·(1.602 x 10⁻¹⁹ C)² / D²

We have to solve THAT ugly mess for ' D '.

Clean up the units first:

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D² x 8.926 x 10⁻¹ = (8.98755 m²) x (1.602)²

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I am shocked, impressed, and amazed !

Are you shocked, impressed, or amazed ?

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aleksandr82 [10.1K]

Answer:

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