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maksim [4K]
2 years ago
5

Question 25 of 25

Physics
1 answer:
gizmo_the_mogwai [7]2 years ago
5 0
Answer :
1.33m/s²
Explanation :
a =vf - vi/t
a =28m/s/2.1s
a = 1.33m/s/s =1.33m/s²
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What is the meaning of physic​
irina [24]

the scientific study of natural forces such as light, sound, heat, electricity, pressure, etc.

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3 years ago
A low-luminosity star has a small and narrow ________, whereas a high-luminosity star has a large and wide one.
vova2212 [387]

A low-luminosity star has a small and narrow ​<u>habitable zone</u>, whereas a high-luminosity star has a large and wide one.

<h3>What is luminosity of a star?</h3>

The radiant power emitted by a light-emitting item over time is measured as luminosity, which is an absolute measure of radiated electromagnetic power (light).

The total quantity of electromagnetic energy released per unit of time by a star, galaxy, or other celestial object is referred to as luminosity in astronomy.

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1 year ago
Reuptake refers to the...
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Reuptake refers to the REABSORPTION of excess neurotransmitter molecules by a sending neuron (Option b).

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4 0
2 years ago
George walks to a friend's house. He walks 850 meters north before he realizes he walked too far.
anyanavicka [17]

Answer:

<h2>44 m/s</h2>

Explanation:

In this problem we are expected to calculate the velocity of Georges movements.

Given data

Total distance covered by  George= 850+250= 1100 meters

Time taken  by  George to cover the total distance= 25 seconds

We know that velocity is, v= distance/ time

Therefore substituting our data into the expression for velocity we have

v= 1100/ 25= 44 m/s

Hence the velocity in m/s is 44

7 0
3 years ago
A 0.10 kg ball of dough is thrown straight up into the air with an initial speed of 15 m/s.
Reptile [31]
<span>Mass of the ball is m = 0.10kg Initial speed of the Ball v = 15m/s a. When the ball is at maximum height the velocity is 0 Momentum of ball = mass x velocity Momentum = 0.10kg x 0 = 0 b. Getting the maximum height, Using the conservation of energy equation KEinitial = mgh 1/2mVin^2 = mgh => h = v^2/2g h = 15^2/2x9.8 = 11.48m => Half Height h = 5.96m Applying the conservation of energy equation at halfway V^2 = 2gh V = square root of (2x9.8x5.96) => V = square root of (116.816) So the velocity at the half way V = 10.81 m/s Momentum M = m x V => M = 0.10 x 10.81 => M = 1.081kg-m/s</span>
6 0
3 years ago
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