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Black_prince [1.1K]
3 years ago
6

On December 26, 2004, a great earthquake occurred off the coast of Sumatra and triggered immense waves (tsunami) that killed som

e 200000 people. Satellites observing these waves from space measured 800 from one wave crest to the next and a period between waves of 1.0 hour.Part AWhat was the speed of these waves in m/s?Express your answer using two significant figures.=Part BWhat was the speed of these waves in km/h ?Express your answer using two significant figures.=
Physics
1 answer:
k0ka [10]3 years ago
5 0

Answers:

a) 222.22 m/s

b) 800.00 km/h

Explanation:

The speed of a wave is given by the following equation:

v=f \lambda

Where:

v is the speed

f=\frac{1}{T} is the frequency, which has an inverse relation with the period T=1 h

\lambda=800 km is the wavelength

Solving with the given units:

v=\frac{1}{T}\lambda

v=\frac{1}{1 h}800 km

v=800.00 km/h This is the speed of the wave in km/h

Transforming this speed to m/s:

v=800.00 \frac{km}{h} \frac{1 h}{3600 s} \frac{1000 m}{1 km}

v=222.22 m/s This is the speed of the wave in m/s

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For the 100 kg roller coaster that comes over the first hill of height 20 meters at 2 m/s, we have:

1) The total energy for the roller coaster at the <u>initial point</u> is 19820 J

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6) The velocity of the roller coaster at <u>point C</u> is 19.91 m/s

1) The total energy for the roller coaster at the <u>initial point</u> can be found as follows:

E_{t} = KE_{i} + PE_{i}

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KE: is the kinetic energy = (1/2)mv₀²

m: is the mass of the roller coaster = 100 kg

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2) The <em>potential energy</em> at point A is:

PE_{A} = mgh_{A} = 100 kg*9.81 m/s^{2}*20 m = 19620 J

Then, the potential energy at <u>point A</u> is 19620 J.

3) The <em>kinetic energy</em> at point B is the following:

KE_{A} + PE_{A} = KE_{B} + PE_{B}

KE_{B} = KE_{A} + PE_{A} - PE_{B}

Since

KE_{A} + PE_{A} = KE_{i} + PE_{i}

we have:

KE_{B} = KE_{i} + PE_{i} - PE_{B} =  19820 J - mgh_{B} = 19820 J - 100kg*9.81m/s^{2}*10 m = 10010 J

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4) The <em>potential energy</em> at <u>point C</u> is zero because h = 0 meters.

PE_{C} = mgh = 100 kg*9.81 m/s^{2}*0 m = 0 J

5) The <em>kinetic energy</em> of the roller coaster at point C is:

KE_{i} + PE_{i} = KE_{C} + PE_{C}            

KE_{C} = KE_{i} + PE_{i} = 19820 J      

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Hence, the velocity of the roller coaster at <u>point C</u> is 19.91 m/s.

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