Answer: 0.35 m/s to the right.
Explanation:
Let's define M1 and V1 as the mass and velocity of the linebacker, and define the right as the positive side.
M1 = 125kg
V1 = 2.5m/s
M2 and V2 as the velocity and mass of the quarterback.
M2 = 80kg
V2 = -3m/s
where V2 has a minus sign because the quarterback is running to the left.
We know that after the collision, both players keep stick togheter, so we can think this as an perfectly inleastic collision, where the velocity of both players can be obtained by:
v = (M1*V1 + M2*V2)/(M1 + M2) = (125kg*2.5m/s - 80kg*3m/s)/(125kg + 80kg)
v = (72.5/205) m/s = 0.35m/s
Because this velocity is positive, this means that both players are moving to the right.
Answer:
P = 4000 [W]
Explanation:
In order to solve this problem, we must first determine the work, which is defined as the product of force by distance.
W = F*d
where:
W = work [J] (units in Joules)
F = force = 1000[N]
d = distance = 2 [m]
W = 1000*2
W = 2000 [J]
And power is defined as the relationship between work and the time in which the work is done.
P = W/t
P = power [W] (units of watts)
t = time = 0.5 [s]
P = 2000/0.5
P = 4000 [W]
Answer:
B. 85.4 N
Explanation:
The tension in the rope at the lowest point of the motion of the ball is antiparallel to the weight of the ball. By Newton's laws we construct the following equation of equilibrium:
(1)
Where:
- Tension in the rope, measured in newtons.
- Weight, measured in newtons.
- Gravitational acceleration, measured in meters per square second.
- Speed of the ball, measured in meters per second.
- Length of the rope, measured in meters.
If we know that
,
,
and
, then the tension in the rope at this point is:
![T = W+\frac{W\cdot v^{2}}{g\cdot L}](https://tex.z-dn.net/?f=T%20%3D%20W%2B%5Cfrac%7BW%5Ccdot%20v%5E%7B2%7D%7D%7Bg%5Ccdot%20L%7D)
![T = W\cdot \left(1+\frac{v^{2}}{g\cdot L} \right)](https://tex.z-dn.net/?f=T%20%3D%20W%5Ccdot%20%5Cleft%281%2B%5Cfrac%7Bv%5E%7B2%7D%7D%7Bg%5Ccdot%20L%7D%20%5Cright%29)
![T = (60\,N)\cdot \left[1+\frac{\left(5\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot (6\,m)} \right]](https://tex.z-dn.net/?f=T%20%3D%20%2860%5C%2CN%29%5Ccdot%20%5Cleft%5B1%2B%5Cfrac%7B%5Cleft%285%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%29%5E%7B2%7D%7D%7B%5Cleft%289.807%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%5Cright%29%5Ccdot%20%286%5C%2Cm%29%7D%20%5Cright%5D)
![T = 85.492\,N](https://tex.z-dn.net/?f=T%20%3D%2085.492%5C%2CN)
Hence, the correct answer is B.
Answer:
Chemical energy to mechanical energy
Explanation: uses gases and fluids to make it thermal then mechanical
Answer:
east
Explanation:
15km east
_______________
X________
8km west
so you are where the xX is so you are still in the eastward direction