Answer:
Part a)

Part b)

Part c)

Part d)

Part e)

Explanation:
Part a)
initial vertical position = 1.02 m
maximum height = 1.80 m





time taken by it to reach this height



Now when it again touch the ground then its speed is given as



time taken by it to reach this height





Part b)
Horizontal velocity



Part c)
vertical velocity is the intial y direction velocity

Part d)
Take off angle is given as


Part e)
initial vertical position = 1.20 m
maximum height = 2.50 m





time taken by it to reach this height



Now when it again touch the ground then its speed is given as



time taken by it to reach this height





 
        
             
        
        
        
Answer:
Option A. 39.2 m/s
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 0 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) = 4 s
Final velocity (v) =?
v = u + gt
Since the initial velocity (u) is 0, the above equation becomes:
v = gt
Thus, inputting the value of g and t, we can obtain the value of v as shown below:
v = 9.8 × 4
v = 39.2 m/s
Therefore, the velocity of the ball at 4 s is 39.2 m/s. 
 
        
                    
             
        
        
        
Answer:
a=0.212 m/s²
Explanation:
Given that
q= 10⁻⁹ C
m = 5 x 10⁻⁹ kg
Magnetic filed ,B= 0.003 T
Speed ,V= 500 m/s
θ= 45°
Lets take acceleration of the mass is a m/s²
The force on the charge due to magnetic filed B
F= q V B sinθ
Also F= m a  ( from Newton's law)
By balancing these above two forces
m a= q V B sinθ



a=0.212 m/s²
 
        
             
        
        
        
Answer:
You should use this for work related questions :/