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Usimov [2.4K]
2 years ago
14

A meteroid is in a circular orbit 600 km above the surface of a distant planet. the planet has the same mass as Earth but has a

radius that is 90% of Earths (where Earths radius is approximately 6370 km).
The acceleration of the meteroid due to the gravitational force exerted by the planet is most nearly

A) 9 m/s^2 toward the center of the planet

B) 9 m/s^2 in the direction of the meteoroids motion

C) 10 m/s^2 toward the center of the planet

D) 10 m/s^2 in the direction of the meteoroids motion​
Physics
2 answers:
taurus [48]2 years ago
6 0
Well, the answer to this question is D) 10 m/s^2 in the direction of the meteoroids motion.
Glad I could help and have a fantastic day!
Also, can you please mark my answer as the brainliest answer?
Thanks.
Llana [10]2 years ago
3 0

Answer:

C)  10 m/s^2 toward the center of the planet

Explanation:

g = GM/r^2

The masses of earth and this planet are the same and the radius is only diffferent by 10% so as gravitational force acceleration is 9.8m/s^2 on earth, it can be estimated to be around 10m/s^2.

Using the third law, we know acceleration is toward the larger mass from attraction, thus having it point toward the center of the planet.

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A spaceship moves radially away from Earth with acceleration 29.4 m/s 2 (about 3g). How much time does it take for sodium street
Gemiola [76]

Answer:

doppler shift's formula for source and receiver moving away from each other:

<em>λ'=λ°√(1+β/1-β)</em>

Explanation:

acceleration of spaceship=α=29.4m/s²

wavelength of sodium lamp=λ°=589nm

as the spaceship is moving away from earth so wavelength of earth should increase w.r.t increasing speed until it vanishes at λ'=700nm

using doppler shift's formula:

<em>λ'=λ°√(1+β/1-β)</em>

putting the values:

700nm=589nm√(1+β/1-β)

after simplifying:

<em>β=0.17</em>

by this we can say that speed at that time is: v=0.17c

to calculate velocity at an acceleration of a=29.4m/s²

we suppose that spaceship started from rest so,

<em>v=v₀+at</em>

where v₀=0

so<em> v=at</em>

as we want to calculate t so:-

<em>t=v/a</em>                                                v=0.17c      ,c=3x10⁸           ,a=29.4m/s²

putting values:

=0.17(3x10⁸m/s)/29.4m/s²

<em>t=1.73x10⁶</em>

7 0
3 years ago
The potential energy of a 1.7 x 10-3 kg particle is described by U (x )space equals space minus (17 space J )space cos open squa
hichkok12 [17]

Answer:

Explanation:

Given a particle of mass

M = 1.7 × 10^-3 kg

Given a potential as a function of x

U(x) = -17 J Cos[x/0.35 m]

U(x) = -17 Cos(x/0.35)

Angular frequency at x = 0

Let find the force at x = 0

F = dU/dx

F = -17 × -Sin(x/0.35) / 0.35

F = 48.57 Sin(x/0.35)

At x = 0

Sin(0) =0

Then,

F = 0 N

So, from hooke's law

F = -kx

Then,

0 = -kx

This shows that k = 0

Then, angular frequency can be calculated using

ω = √(k/m)

So, since k = 0 at x = 0

Then,

ω = √0/m

ω = √0

ω = 0 rad/s

So, the angular frequency is 0 rad/s

4 0
3 years ago
The air also contained a small amount of argon.
andriy [413]

Answer:

When argon changes from a gas to a liquid, the forces between the molecules become stronger so the particles become closer together and come into come into contact more often. The particles move at a less faster rate as the have less kinetic energy due to decrease in temperature. When argon changes from a liquid to a solid, the forces become even stronger so the particles are arranged in fixed positions and vibrate around a fixed point as they cannot move past each other

8 0
2 years ago
A balloon is launched at 2.5 m every second, how far did it travel in 10 seconds?
Elina [12.6K]

Answer:

25 meters

Explanation:

1 sec is 2.5, 1x10 so 2.5x10=25

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An industry uses natural gas for manufacturing and uses the waste heat to produce electricity. This is an example of which proce
Lana71 [14]

answer is chemical process

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