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Usimov [2.4K]
3 years ago
14

A meteroid is in a circular orbit 600 km above the surface of a distant planet. the planet has the same mass as Earth but has a

radius that is 90% of Earths (where Earths radius is approximately 6370 km).
The acceleration of the meteroid due to the gravitational force exerted by the planet is most nearly

A) 9 m/s^2 toward the center of the planet

B) 9 m/s^2 in the direction of the meteoroids motion

C) 10 m/s^2 toward the center of the planet

D) 10 m/s^2 in the direction of the meteoroids motion​
Physics
2 answers:
taurus [48]3 years ago
6 0
Well, the answer to this question is D) 10 m/s^2 in the direction of the meteoroids motion.
Glad I could help and have a fantastic day!
Also, can you please mark my answer as the brainliest answer?
Thanks.
Llana [10]3 years ago
3 0

Answer:

C)  10 m/s^2 toward the center of the planet

Explanation:

g = GM/r^2

The masses of earth and this planet are the same and the radius is only diffferent by 10% so as gravitational force acceleration is 9.8m/s^2 on earth, it can be estimated to be around 10m/s^2.

Using the third law, we know acceleration is toward the larger mass from attraction, thus having it point toward the center of the planet.

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A vessel (see the figure) comprises of into two chambers
r-ruslan [8.4K]

Answer:

(C) 2P

Explanation:

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(PV / T) before = (PV / T) after

Chamber X starts at pressure P, volume V, and temperature T.  At equilibrium, the pressure is Px, the volume is Vx, and temperature 3T.

PV / T = Px Vx / 3T

Chamber Y starts at pressure P, volume V, and temperature T.  At equilibrium, the pressure is Py, the volume is Vy, and temperature T.

PV / T = Py Vy / T

Substituting and simplifying:

Px Vx / 3T = Py Vy / T

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Since the chambers are at equilibrium, Px = Py:

Vx / 3 = Vy

Vx = 3 Vy

The total volume is the same as before, so:

Vx + Vy = 2V

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The pressure in chamber Y (and chamber X) doubles at equilibrium.

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