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horsena [70]
3 years ago
10

A circular loop has radius R and carries current I2 in a clockwise direction. The center of the loop is a distance D above a lon

g, straight wire.
What is the magnitude of the current I1 in the wire if the magnetic field at the center loop is zero? Express your answer in terms of the variables I2, R, D, and appropriate constants (μ0 and π).
Physics
1 answer:
romanna [79]3 years ago
5 0

Answer:

I_{1} = (πDI_{2})/R

Explanation:

If we define the magnitude of the field as B, then we have:

Total magnitude of the field B_{t} = magnitude of the field B_loop + magnitude of the field B_wire. The total magnitude is equivalent to zero. Therefore, the field B_loop has an inward direction while the field B_wire has an outward direction.

B_loop = (μ0)*(I_{2})/2*R

B_wire = (μ0)*(I_{1})/2*π*D

Thus:

B_loop = B_wire at the center of the loop.

(μ0)*(I_{2})/2*R = (μ0)*(I_{1})/2*π*D

I_{1} = (πDI_{2})/R

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Answer:

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Explanation:

The average velocity of an object is defined as the ratio between the displacement and the time taken:

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Therefore, their average velocity is

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Learn more about average velocity:

brainly.com/question/5248528

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