Answer:
a) 113N
b) 0.37
Explanation:
a) Using the Newton's second law:
\sum Fx =ma
Since the crate doesn't move (static), acceleration will be zero. The equation will become:
\sum Fx = 0
\sumFx = Fm - Ff = 0.
Fm is the applied force
Ff is the frictional force
Since Fm - Ff = 0
Fm = Ff
This means that the applied force is equal to the force of friction if the crate is static.
Since applied force is 113N, hence the magnitude of the static friction force will also be 113N
b) Using the formula
Ff = nR
n is the coefficient of friction
R is the reaction = mg
R = 31.2 × 9.8
R = 305.76N
From the formula
n = Ff/R
n = 113/305.76
n = 0.37
Hence the minimum possible value of the coefficient of static friction between the crate and the floor is 0.37
Answer:
The magnitude of the magnetic force this particle experiences is
.
Explanation:
Given that,
Velocity v= (3i-5j+k) m/s
Magnetic field B=(i+2j-k) T
We need to calculate the value 

We need to calculate the magnitude of the magnetic force this particle experiences
Using formula of magnetic force

Put the value into the formula



Hence, The magnitude of the magnetic force this particle experiences is
.
Answer:
The pressure will be of 399.17 mmHg.
Explanation:
p1= 754 mmHg
V1= 4.5 L
p2= ?
V2= 8.5 L
p1*V1 = p2*V2
p2= (p1*V1)/V2
p2= 399.17 mmHg
Answer:
5 x biger
Explanation:
becuze if it ia 5× more it nids 5×more force to be =
Answer:
Interference
Explanation:
When two traveling waves traveling waves along the same path are superimposed(combine). The superimposition of these two waves results in the production of a resultant wave which is defined by the net effect of the two waves. Wave interference occurs most types of waves including radio wave, light, acoustic waves and other wave types. Alternating sound between loud and Zero is heard as the two speakers emit identical pure tones because the resultant amplitude after the interference of the two sound waves is the vector sum of each of their amplitudes. A loud sound is heard, when the crest of both waves meets each other and a zero is heard if the crest of one meets the trough of the other as they cancel out.