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statuscvo [17]
3 years ago
11

A sample of gas has an initial volume of 23.6 l at a pressure of 1.52 atm . if the sample is compressed to a volume of 10.5 l: ,

what will its pressure be? (assume constant temperature.)
Physics
1 answer:
nataly862011 [7]3 years ago
7 0

New pressure=3.42 atm

Explanation:

using Boyle's law

P1 V1= P2 V2

P1= initial pressure

V1= initial volume

P2= final pressure

V2=final volume

23.6 (1.52)=P2 (10.5)

P2=3.42 atm

so final pressure= 3.42 atm

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There is the more role of the moon than the sun to occur tides in the oceans,why?
Nana76 [90]

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2 years ago
An object initially at rest experiences an acceleration of 0.281 m/s2 to the South for a time of 5.44 seconds. It then increases
andre [41]

Answer:

12.0 meters

Explanation:

Given:

v₀ = 0 m/s

a₁ = 0.281 m/s²

t₁ = 5.44 s

a₂ = 1.43 m/s²

t₂ = 2.42 s

Find: x

First, find the velocity reached at the end of the first acceleration.

v = at + v₀

v = (0.281 m/s²) (5.44 s) + 0 m/s

v = 1.53 m/s

Next, find the position reached at the end of the first acceleration.

x = x₀ + v₀ t + ½ at²

x = 0 m + (0 m/s) (5.44 s) + ½ (0.281 m/s²) (5.44 s)²

x = 4.16 m

Finally, find the position reached at the end of the second acceleration.

x = x₀ + v₀ t + ½ at²

x = 4.16 m + (1.53 m/s) (2.42 s) + ½ (1.43 m/s²) (2.42 s)²

x = 12.0 m

5 0
3 years ago
radio waves are electromagnetic waves that travel at the speed of light 300 000 kilometers per second what is the wave length of
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<h2>Answer:</h2>

<h2>3m</h2>

<h3>The wavelength of 100-MHz radio waves is 3 m, yet using the sensitivity of the resonant frequency to the magnetic field strength, details smaller than a millimeter can be imaged.</h3>

<h2>Hope this helps you ❤️</h2>

<h2>MaRk mE aS braiNliest ❤️</h2>

3 0
2 years ago
How much work must be done to bring three electrons from a great distance apart to 5.0×10^−10 m from one another (at the corners
Inessa05 [86]

Answer:

1.38 x 10^-18 J

Explanation:

q = - 1.6 x 10^-19 C

d = 5 x 10^-10 m

the potential energy of the system gives the value of work done

The formula for the potential energy is given by

U =\frac{Kq_{1}q_{2}}{d}

So, the total potential energy of teh system is

U =\frac{Kq_{1}q_{2}}{d}+\frac{Kq_{2}q_{3}}{d}+\frac{Kq_{1}q_{3}}{d}

As all the charges are same and the distance between the two charges is same so the total potential energy becomes

U =3\times \frac{Kq^{2}}{d}

K = 9 x 10^9 Nm^2/C^2

By substituting the values

U =3\times \frac{9\times 10^{9}\times \ 1.6 \times 1.6 \times 10^{-38}}{5\times 10^{-10}}

U = 1.38 x 10^-18 J

6 0
3 years ago
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