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marissa [1.9K]
3 years ago
8

What is Keq for an electrochemical reaction involving the transfer of 3 electrons, if E°cell = 0.652 V at

Physics
1 answer:
madam [21]3 years ago
6 0

Answer:

2.49 V.

Explanation:

The formula which relates the equilibrium condition in the electrochemical cell is,

logk_{eq}=\frac{n}{0.059}  E_{cell} ^{0}

Given that the number of electron is 3 and the value of E^{0} _{cell} is  0.652 V.

Now put these values in above equation.

logk_{eq}=\frac{3}{0.059}  (0.652 V)\\logk_{eq}=33.15 V\\k_{eq}=e^{33.15}V\\k_{eq}=2.49V

Therefore, the value of Keq for an electrochemical reaction is 2.49 V.

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alexira [117]

Answer:

A

Explanation:

3 0
2 years ago
Law of Conservation of Energy.
Tems11 [23]
Energy cannot be created nor be destroyed
3 0
3 years ago
If a ping pong ball and a golf ball are both moving in the same direction with the same amount of kinetic energy, the speed of t
Liono4ka [1.6K]

If the kinetic energy of each ball is equal to that of the other,
then

(1/2) (mass of ppb) (speed of ppb)² = (1/2) (mass of gb) (speed of gb)²

Multiply each side by 2:

      (mass of ppb) (speed of ppb)² = (mass of gb) (speed of gb)²

Divide each side by (mass of gb) and by (speed of ppb)² :

     (mass of ppb)/(mass of gb)  =  (speed of gb)²/(speed of ppb)²

Take square root of each side:

       √ (ratio of their masses)  =  ( 1 / ratio of their speeds)²

By trying to do this perfectly rigorously and elegantly, I'm also
using up a lot of space and guaranteeing that nobody will be
able to follow what I have written.  Let's just come in from the
cold, and say it the clear, easy way:

If their kinetic energies are equal, then the product of each
mass and its speed² must be the same number.

If one ball has less mass than the other one, then the speed²
of the lighter one must be greater than the speed² of the heavier
one, in order to keep the products equal.

The pingpong ball is moving faster than the golf ball.

The directions of their motions are irrelevant.

5 0
3 years ago
In the Hydrogen atom, the energy spacing between the is 4.07 x 101 J (Joules). When an is the frequency of the photons emitted?
agasfer [191]

Answer:

The frequency of the photon is 3.069\times10^{14}\ Hz.

Explanation:

Given that,

Energy E=4.07\times10^{-19}\ J

We need to calculate the energy

Using relation of energy

E_{4}-E_{2}=\Delta E

Where, \Delta E =  energy spacing

4h\nu-2h\nu=4.07\times10^{-19}

\nu=\dfrac{4.07\times10^{-19}}{2h}

Put the value of h into the formula

\nu=\dfrac{4.07\times10^{-19}}{2\times6.63\times10^{-34}}

\nu=3.069\times10^{14}\ Hz

Hence, The frequency of the photon is 3.069\times10^{14}\ Hz.

4 0
3 years ago
Which statements best characterize conductors? Check all that apply.
romanna [79]
It would be the first one and the third one
5 0
3 years ago
Read 2 more answers
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