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3 years ago

What is Keq for an electrochemical reaction involving the transfer of 3 electrons, if E°cell = 0.652 V at

Physics

1 answer:

madam [21]3 years ago

6 0

Answer:

2.49 V.

Explanation:

The formula which relates the equilibrium condition in the electrochemical cell is,

$logk_{eq}=\frac{n}{0.059} E_{cell} ^{0}$

Given that the number of electron is 3 and the value of $E^{0} _{cell}$ is 0.652 V.

Now put these values in above equation.

$logk_{eq}=\frac{3}{0.059} (0.652 V)\\logk_{eq}=33.15 V\\k_{eq}=e^{33.15}V\\k_{eq}=2.49V$

Therefore, the value of Keq for an electrochemical reaction is 2.49 V.

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How does reflection differ from refraction and diffraction?

shtirl [24]

Answer: Reflection is the only process in which the wave does not continue moving forward.

Explanation:

Reflection is a process in which the direction of the wave changes when it is exposed to a bounce off barrier. Refraction can be defined as the change in the direction of the wave when the wave passes through one medium to another. Diffraction is a process in which the direction of the wave changes when the wave passes through a particular opening near the barrier.

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3 years ago

I would love to stretch a wire from our house to the Shop so I can 'call' my husband in for meals. The wire could be tightened t

dezoksy [38]

Note: I'm not sure what do you mean by "weight 0.05 kg/L". I assume it means the mass per unit of length, so it should be "0.05 kg/m".

Solution:
The fundamental frequency in a standing wave is given by
$f= \frac{1}{2L} \sqrt{ \frac{T}{m/L} }$
where L is the length of the string, T the tension and m its mass. If we plug the data of the problem into the equation, we find
$f= \frac{1}{2 \cdot 24 m} \sqrt{ \frac{240 N}{0.05 kg/m} }=1.44 Hz$

The wavelength of the standing wave is instead twice the length of the string:
$\lambda=2 L= 2 \cdot 24 m=48 m$

So the speed of the wave is
$v=\lambda f = (48 m)(1.44 Hz)=69.1 m/s$

And the time the pulse takes to reach the shop is the distance covered divided by the speed:
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4 years ago

What is the resulting velocity of the launcher if the net force on the launcher is equal to the reaction force?

xz_007 [3.2K]

Answer:

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3 years ago

The luxury liner Queen Elizabeth 2 has a diesel-electric powerplant with a maximum power of 90 MW at a cruising speed of 31.5 kn

AlexFokin [52]

Answer:

5558643.69 N

Explanation:

F = Force

v = Velocity = 31.5 knots

Converting to m/s

$1\ knot=0.514\ m/s$

$31.5\ knot=31.5\times 0.514\ m/s=16.191\ m/s$

Power is given by

$P=Fv\\\Rightarrow F=\frac{P}{v}\\\Rightarrow F=\frac{90\times 10^6}{16.191}\\\Rightarrow F=5558643.69\ N$

The forward force is exerted on the ship at this highest attainable speed is 5558643.69 N

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4 years ago

In an experiment in space, one proton is held fixed and another proton is released from rest a distance of 1.00 mm away. part a

mihalych1998 [28]

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3 years ago