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3 years ago

What is Keq for an electrochemical reaction involving the transfer of 3 electrons, if E°cell = 0.652 V at

Physics

1 answer:

madam [21]3 years ago

6 0

Answer:

2.49 V.

Explanation:

The formula which relates the equilibrium condition in the electrochemical cell is,

$logk_{eq}=\frac{n}{0.059} E_{cell} ^{0}$

Given that the number of electron is 3 and the value of $E^{0} _{cell}$ is 0.652 V.

Now put these values in above equation.

$logk_{eq}=\frac{3}{0.059} (0.652 V)\\logk_{eq}=33.15 V\\k_{eq}=e^{33.15}V\\k_{eq}=2.49V$

Therefore, the value of Keq for an electrochemical reaction is 2.49 V.

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