Answer:
v₁f = 0.5714 m/s (→)
v₂f = 2.5714 m/s (→)
e = 1
It was a perfectly elastic collision.
Explanation:
m₁ = m
m₂ = 6m₁ = 6m
v₁i = 4 m/s
v₂i = 2 m/s
v₁f = ((m₁ – m₂) / (m₁ + m₂)) v₁i + ((2m₂) / (m₁ + m₂)) v₂i
v₁f = ((m – 6m) / (m + 6m)) * (4) + ((2*6m) / (m + 6m)) * (2)
v₁f = 0.5714 m/s (→)
v₂f = ((2m₁) / (m₁ + m₂)) v₁i + ((m₂ – m₁) / (m₁ + m₂)) v₂i
v₂f = ((2m) / (m + 6m)) * (4) + ((6m -m) / (m + 6m)) * (2)
v₂f = 2.5714 m/s (→)
e = - (v₁f - v₂f) / (v₁i - v₂i) ⇒ e = - (0.5714 - 2.5714) / (4 - 2) = 1
It was a perfectly elastic collision.
Does Physics involve science? Because I think there's a chemical bond between us. :3
Answer:
a) The acceleration is 2.14 m/s^{2}
b) The distance traveled by the car is 65.61 m
c) The average velocity is 18.75 m/s
Explanation:
Using the equations that describe an uniformly accelerated motion:
a) 
b) 
c) 
Answer:
he affirmations the correct ones are: A and D
Explanation:
To find out which expressions are correct, let's calculate the work and power done by each person
the expression for work is W = F and
the expression for power is P = W / t
In this case the work is positive because the beast is in the same direction of displacement.
Ted
W₁ = 10 1.5
W₁ = 15 J
P₁ = 15/1
P₁ = 15 w
Johnny
the job
W₂ = 10 1.5
W₂ = 15 J
the potential
P₂ = 15/2
P₂ = 7.5 w
therefore we see that the work of both is the same, but Ted developed twice as much power as Johnny
when resisting the affirmations the correct ones are: A and D
