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zysi [14]
3 years ago
13

Displacement vectors of 4 km north, 2km south, 5 km north, and 5km south combine to a total displacement of A 2 km south B 16 km

south C.16 km south D 2km north?
Physics
2 answers:
irga5000 [103]3 years ago
8 0
<h3><u>Answer;</u></h3>

A. 2 km North

<h3><u>Explanation;</u></h3>
  • <em><u>Displacement is a vector quantity that describes the shortest distance  or path from an initial position to the final position. </u></em>
  • Displacement combines both distance and direction of a motion along a straight line from the origin to the final position of a point.
  • In this case; we start with; 4 km north and 2 km south; to get 2 km North from the original position, adding 5 km north, we get 7 km north, the adding 5 km south we get a total displacement of 2 km north.

prohojiy [21]3 years ago
4 0
I would prolly say C. 16 km south.
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1 poir
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D) 735 J(oules)

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A particle is moving with velocity v(t) = t2 _ 9t + 18 with distance, s measured in meters, left or right of zero, and t measure
Alex787 [66]
V = t^2 - 9t + 18

position, s
s = t^3 /3 - 4.5t^2 +18t + C

       t = 0, s = 1 => 1=C => s = t^3/3 -4.5t^2 + 18t + 1

Average velocity: distance / time

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t = 5 s

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     speed = |-2| m/s = 2 m/s
 
Moving right
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     => t > 6 and t > 3 => t > 6 s => Interval (6,8)

    => t < 6 and t <3 => t <3 s => interval (0,3)

    

Going faster and slowing dowm

acceleration, a = v' = 2t - 9
     a > 0 => 2t - 9 > 0 => 2t > 9 => t > 4.5 s
     Then, going faster in the interval (4.5 , 8) and slowing down in (0, 4.5)
     


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