Question

A sample of gas contains four gases (He, Ne, Ar, and Xe) with the following partial pressures: He (43 mm Hg), Ar (835 mm Hg), and Xe (111 mm Hg). If the total pressure in the container is 1355 mm Hg, what is the partial pressure of Ne in the sample?

Answer 1

Answer:

Partial pressure of Ne = 366 mmHg

Explanation:

In a mixture, the sum of partial pressures for each gas, is the total pressure for the system.

Partial pressure He: 43 mmHg

Partial pressure Ar: 835 mmHg

Partial pressure Xe: 111 mmHg

Partial pressure Ne: ?

Total pressure = 1355 mmHg

43 + 835 + 111 + x  = 1355

989 + x = 1355

x = 1355 - 989 → 366