What is the measure of the concentration of hydrogen (H+) ion or (H2O+) ions in a solution known as?

How many liters are in 3.45 moles of oxygen gas at STP?

just olya [345]

Answer:

22.4L of one mole of any gas

or you can use PV=nRT

3.45*22.4=77.28

Explanation:

5 0

3 years ago

A student ran the following reaction in the laboratory at 671 K: 2NH3(g) N2(g) + 3H2(g) When she introduced 7.33×10-2 moles of N

vaieri [72.5K]

Answer:

Kc = 8.05x10⁻³

Explanation:

This is the equilibrium:

2NH₃(g) ⇄ N₂(g) + 3H₂(g)

Initially 0.0733

React 0.0733α α/2 3/2α

Eq 0.0733 - 0.0733α α/2 0.103

We introduced 0.0733 moles of ammonia, initially. So in the reaction "α" amount react, as the ratio is 2:1, and 2:3, we can know the moles that formed products.

Now we were told that in equilibrum we have a [H₂] of 0.103, so this data can help us to calculate α.

3/2α = 0.103

α = 0.103 . 2/3 ⇒ 0.0686

So, concentration in equilibrium are

NH₃ = 0.0733 - 0.0733 . 0.0686 = 0.0682

N₂ = 0.0686/2 = 0.0343

So this moles, are in a volume of 1L, so they are molar concentrations.

Let's make Kc expression:

Kc= [N₂] . [H₂]³ / [NH₃]²

Kc = 0.0343 . 0.103³ / 0.0682² = 8.05x10⁻³

3 0

3 years ago

Does the color of bell peppers effect the number of seeds inside? Please someone help ASAP I need it today

Mekhanik [1.2K]

I don't think so. "It's not a matter of pigment discrimination: Red and yellow bell peppers are essentially just green peppers that have been allowed to ripen"

3 0

3 years ago

What is the advantage of rusting

Naddika [18.5K]

Answer:

Provide more strength

Explanation:

Rust is metal that has been oxidised . Oxides are usually more fragile and porous than their crystals metal equivalents. Some oxides, such as Aluminum oxide, are useful because they have a thin, strong shell that protects the metal from further corrosion.

8 0

3 years ago

1. The solubility of lead(II) chloride at some high temperature is 3.1 x 10-2 M. Find the Ksp of PbCl2 at this temperature.

solniwko [45]

Answer:

1) The solubility product of the lead(II) chloride is $1.2\times 10^{-4}$ .