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eimsori [14]
3 years ago
12

What effect does freezing water into a ice cube have on its mass

Physics
1 answer:
Vanyuwa [196]3 years ago
8 0
The "stuff" (molecules) in water is more tightly packed than in ice, so water has greater density than ice. Don't let the fact that ice is a solid fool you! As water freezes it expands. So, ice has more volume (it takes up more space, but has less density) than water.
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Question 10 of 10
Bad White [126]

Answer:

D. The Federal Reserve Bank can provide a short-term loan to banks

to prevent them from running out of money.

Explanation:

A bank run occurs when a large number of depositors withdraw their deposits simultaneously from a bank.

As the number of withdraws increases, the available cash in the bank decreases until a point that the bank can't give depositors their money.

In these situations, The Federal Reserve Bank acts as a lender of last resort that helps to reinforce the effect of deposit insurance, and to reassure bank customers that they will not lose their money.

5 0
4 years ago
Why do blades come in different lengths in a jig saw sander?​
trasher [3.6K]

Answer:

To determine the minimum blade length, add 1" to the workpiece thickness. One type of material, and some materials can be cut by more than one type of blade. No matter the material, there's likely a jigsaw blade designed specifically for. Armed with the right blade, follow these pointers to make your work go (and cut) .

Explanation:

6 0
3 years ago
An unknown amount of a radioactive isotope with a half-life of 2.0 h was observed for 6.0 h. if the amount of the isotope remain
Grace [21]

The original amount of the radioactive isotope will be 8 grams.

<h3 /><h3>What is the half-life of radioisotopes?</h3>

The amount of time required for half of a radioisotope's nuclide to decay, or change into a different species, is known as its half-life. The conversions release either beta or alpha particles, and the response can be monitored by counting the particles released.

Given that an unknown amount of a radioactive isotope with a half-life of 2.0 h was observed for 6.0 h. if the amount of the isotope remaining after 6.0 h was 24 g.

The original amount will be calculated as below:-

( 2 / 6 ) = ( Original amount / 24 )

Original amount = 4 x 2

Original amount = 8 grams

Therefore, the original amount of the radioactive isotope will be 8 grams.

To know more about the half-life of radioisotopes follow

brainly.com/question/1783783

#SPJ4

5 0
2 years ago
What are the two opposing forces that keep stars between collapsing and inflating?
boyakko [2]
The answer is pressure and gravity
5 0
3 years ago
Assume that, when we walk, in addition to a fluctuating vertical force, we exert a periodic lateral force of amplitude 25 NN at
dexar [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From the question we are told

   The amplitude of the lateral  force is  F = 25 \  N

   The frequency is   f = 1 \  Hz

   The mass of the bridge per unit length is  \mu  =  2000 \  kg /m

    The length of the central span is  d =  144 m

     The oscillation amplitude of the section  considered at the time considered is  A = 75 \ mm =  0.075 \  m

      The time taken for the undriven oscillation to decay to \frac{1}{e}  of its original value is  t = 6T

Generally the mass of the section considered is mathematically represented as

            m =  \mu  *  d

=>        m =  2000 * 144

=>        m =  288000 \ kg

Generally the oscillation amplitude of the section after a  time period  t is mathematically represented as

                 A(t) = A_o e^{-\frac{bt}{2m} }

Here b is the damping constant and the A_o is the amplitude of the section when it was undriven

So from the question  

               \frac{A_o}{e}  = A_o e^{-\frac{b6T}{2m} }

=>            \frac{1}{e}  =e^{-\frac{b6T}{2m} }

=>          e^{-1} =e^{-\frac{b6T}{2m} }

=>           -\frac{3T b}{m}  =  -1

=>         b  = \frac{m}{3T}

Generally the amplitude of the section considered is mathematically represented as

           A =  \frac{n * F }{ b *  2 \pi }

=>       A =  \frac{n * F }{ \frac{m}{3T}  *  2 \pi }

=>       n =  A  *  \frac{m}{3}  *  \frac{2\pi}{25}

=>       n = 0.075 *  \frac{288000}{3}  *  \frac{2* 3.142 }{25}

=>       n = 1810 \ people

3 0
3 years ago
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