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sdas [7]
3 years ago
8

What human practices are destroying the rain forest?

Physics
1 answer:
marissa [1.9K]3 years ago
6 0
Deforestation, the chopping off of the trees that can take thousands or even millions of years to grow again<span />
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Pangaea is the name given for "all land" of Earth. This name is used by Geologists to describe their theory of Earth's original
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Pangaea one major super-continent.
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3 years ago
In which of the following cases is work being done on an object? Question 2 options: Pushing against a locked door Carrying a bo
Serggg [28]

As we know that work done is defined as product of force and displacement in the direction of applied force

so we can say it is

W = F.d

or we can say

W = Fdcos\theta

so we will have following options

A)Pushing against a locked door

There is no work done in above case as there will be no displacement in that case so work done is ZERO

B) Carrying a box down a corridor

While we move done and carrying a box then work done by gravity on the box while our work done is negative work.

C) Pulling a trailer up a hill

In above case our work done to pull a box up a hill is positive work as we need to work against gravity

D)  Suspending a heavy weight with a strong chain

During suspension there is no displacement so there will be no work done in above case

so correct answer will be

<em>Pulling a trailer up a hill</em>


6 0
4 years ago
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SomeOne please help me will give BRAILIEST!!!!!!!!
ale4655 [162]
That is false they are slightly tilted in an up ngle
6 0
3 years ago
Read 2 more answers
What's the value of 1,152 Bri in joules?
adelina 88 [10]
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(1,152 BTU) x (1,055.06 joule/BTU)=<span>1,215,429.12</span>

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6 0
3 years ago
A certain car traveling 33.0mph skids to a stop in 39m from the point where the brakes were applied. In approximately what dista
Greeley [361]

Answer: 156.02 metre.

Explanation:

Give that a certain car traveling 33.0mph skids to a stop in 39m from the point where the brakes were applied.

Let us use third equation of motion,

V^2 = U^2 + 2as

Since the car is decelerating, V = 0

And acceleration a will be negative.

U = 33 mph

S = 39 m

Substitute both into the formula

0 = 33^2 - 2 × a × 39

0 = 1089 - 78a

78a = 1089

a = 1089 / 78

a = 13.96 m/h^2

If we assume that the car decelerate at the same rate.

the distance the car will stop had it been going 66.0mph will be achieved by using the same formula

V^2 = U^2 + 2as

0 = 66^2 - 2 × 13.96 × S

4356 = 27.92S

S = 4356 / 27.92

S = 156.02 m

Therefore, the car would stop at

156.02 m

8 0
3 years ago
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