Answer:
28.81 m
Explanation:
Ff = -123
m * a = -123
(29.8+10.3) * a = -123
a = -123/40.1 = -3.07
We know,
v^2 = u^2 + 2as
0^2 = 13.3^2 + 2*(-3.07)*s
s = 176.89/6.14 = 28.81
[ If there's a problem with the solution, pleaase let me know ]
-- The truck begins the scenario moving at 6 m/s.
-- After increasing its speed at the rate of 2 m/s² for 12 seconds,
it has gained (2 x 12) = 24 m/s of speed, and it's then moving
at 30 m/s.
-- The truck's average speed during the 12 seconds is (1/2) (6 + 30) = 18 m/s
-- Traveling at an average speed of 18 m/s for 12 seconds,
the truck travels
(18 m/s) x (12 sec) = 216 meters
Answer: 0.00000938422m^3
Explanation:
dV=Vø*β*(t1-tø)
The parameters are
dV is the change in volume after temperature increase
Vø =0.607 *10^-3m3 is the initial vokume of coffe at 16.2^0 C
β= coefficient of volume expansion of water at 16.2^0 C is 0.0002/0C
t1= 93.5^0C final temperature
tø=16.2^0 C
Therefore
dV=0.607 *10^-3 *0.0002*(93.5-16.2)
dV= 0.00000938422m^3
This is the volume of coffee that will spill over the container
Velocity probably well that’s what i would put
