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2 years ago

When measuring the potential difference across a component, you need

Physics

2 answers:

Lorico [155]2 years ago

6 0

Answer:

Measuring potential difference Potential difference is measured using a device called a . Just like ammeters, some types have a pointer on a dial, but most have a digital display. However, unlike an ammeter, you must connect the voltmeter in parallel to measure the potential difference across a component in a circuit.

NISA [10]2 years ago

4 0

To measure the potential difference across a component, a voltmeter must be placed in parallel with that component in order to measure the difference in energy from one side of the component to the other. Potential difference is also known as voltage and is measured in volts (V).

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A box is sliding down an incline tilted at a 16.0 angle above horizontal. The box is initially sliding down the incline at a spe

blsea [12.9K]

Answer:

d) 1.44m

Explanation:

According to Newton's second law:

$\sum F=m.a\\$

analyzing the horizontal components of the force:

$\sum F_x=mg*sin(\theta)-\µ*m.g*cos(\theta)\\\sum F_x=m*9.8*(sin(16^o)-0.420*cos(16^o))\\\sum F_x=-1.25m$

applying the second law

$-1.25m=m.a\\a=-1.25m/s^2$

given the acceleration we can calculate the distances traveled before stopping:

$(v_f)^2=(v_o)^2+2.a.\Delta x\\0=(1.90m/s)^2-2(1.25)*\Delta x\\\Delta x=1.44m$

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3 years ago

How are land-use laws in the United States different from the land-use laws inherited from England?

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private property owners in the United States can restrict public access to their land

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2 years ago

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Sergio [31]

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3 years ago

What rock type would most likely be found in the location marked by the black rectangle in the diagram below?

pychu [463]

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2 years ago

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Your ear is capable of differentiating sounds that arrive at each ear just 0.34 ms apart, which is useful in determining where l

goblinko [34]

Answer:

Δt = 5.29 x 10⁻⁴ s = 0.529 ms

Explanation:

The simple formula of the distance covered in uniform motion can be used to find the interval between when the sound arrives at the right ear and the sound arrives at the left ear.

$\Delta s = v\Delta t\\\\\Delta t = \frac{\Delta s}{v}$

where,

Δt = required time interval = ?

Δs = distance between ears = 18 cm = 0.18 m

v = speed of sound = 340 m/s

Therefore,

$\Delta t = \frac{0.18\ m}{340\ m/s}$

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2 years ago