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nordsb [41]
3 years ago
13

An inflatable raft (unoccupied) floats down a river at an approximately constant speed of 5.6 m/s. A child on a bridge, 71 m abo

ve the river, sees the raft in the river below and attempts to drop a small stone onto the raft. The child releases the stone from rest. In order for the stone to hit the raft, what must be the horizontal distance between the raft and the bridge when the child releases the stone?
Physics
1 answer:
saveliy_v [14]3 years ago
3 0

Answer:

21.28 m

Explanation:

height, h = 71 m

velocity of raft, v = 5.6 m/s

let the time taken by the stone to reach to raft is t.

use second equation of motion for stone

h = ut + \frac{1}{2}at^{2}

u = 0 m/s, h = 71 m, g = 9.8 m/s^2

71 = 0 + 0.5 x 9.8 x t^2

t = 3.8 s

Horizontal distance traveled by the raft in time t

d = v x t = 5.6 x 3.8 = 21.28 m

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Answer:

31.55 m/s

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4 0
3 years ago
Explain what effect losing a gamma ray has on a nucleus.
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Answer:

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2 years ago
How can we realize that light travel in straight line ?​
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U.
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Answer:

1. F and G.

2. D

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This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

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Motion can be defined as a change in the location (position) of a physical object or body with respect to a reference point.

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7 0
3 years ago
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8 0
3 years ago
Read 2 more answers
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