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aliya0001 [1]
4 years ago
14

How do S and P waves move through a solid material?

Chemistry
1 answer:
abruzzese [7]4 years ago
6 0

P waves move quickly and S waves move slowly through solids,

Explanation:

S and P waves can move through a solid material. P waves generally moves quickly and S-waves move slowly through solids.

S and P waves elastic seismic waves.

  • P waves are primary waves travels through any material medium. They move faster than S-waves.
  • S waves are secondary waves that moves through solid only. They are shear waves.
  • They cannot move through liquids and gases because these materials cannot be sheared.

At a seismic station, P waves arrives first because they have a higher velocity

Learn more:

Seismograph brainly.com/question/11292835

#learnwithBrainly

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What type of bonding is found in the compound of2?
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Answer:

chemical bond

Explanation:

because atom can join together by forming a chemical bond

7 0
4 years ago
How many protons, neutrons, and electrons make up an ion of
yKpoI14uk [10]

Answer:

protons=15

electron=15

neutron=16

6 0
3 years ago
The heat capacity of water is 1cal degree'g1 (1 calorie per degree centigrade, per gram). You are given 1 gallon of water at 25
sdas [7]

Answer:

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

Explanation:

Q=mc\Delta T

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance  

ΔT = change in temperature of the substance

We have :

Volume of water = V = 1 gal = 4546.09 mL

Density of water , d= 1 g/mL

mass of water = m = d × V = 1g/mL × 4546.09 mL =  4546.09 g

Specific heat of water = c = 1 Cal/g°C

ΔT = 100°C - 25°C = 75 °C

9 (boiling pint of water is 100°C)

Heat absorbed by the water to make it boil:

Q= 4546.09 g\times 1 Cal/g^oC\times 75^oC=340,956.75 Cal

1 calorie = 4.184 J

Q=\frac{340,956.75}{4.184} J = 81,490.62 J

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

5 0
3 years ago
When methane ( CH4 ) burns, it reacts with oxygen gas to produce carbon dioxide and water. The unbalanced equation for this reac
slega [8]
<h2>Answer:</h2>1.33*10^{-2}grams

<h2>Explanations</h2>

The complete balanced equation for the given reaction is expressed as;

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)

Given the following parameters

Mass of CH4 = 5.90×10^−3 g = 0.0059grams

Determine the moles of methane

\begin{gathered} moles\text{ of CH}_4=\frac{mass}{molar\text{ mass}} \\ moles\text{ of CH}_4=\frac{0.0059}{16.04} \\ moles\text{ of CH}_4=0.000368moles \end{gathered}

According to stoichimetry, 1 mole of methane produces 2 moles of water, hence the moles of water required will be:

\begin{gathered} moles\text{ of H}_2O=\frac{2}{1}\times0.000368 \\ moles\text{ of H}_2O=0.000736moles \end{gathered}

Determine the mass of water produced

\begin{gathered} Mass\text{ of H}_2O=moles\times molar\text{ mass} \\ Mass\text{ of H}_2O=0.000736\times18.02 \\ Mass\text{ of H}_2O=0.0133grams=1.33\times10^{-2}grams \end{gathered}

Therefore the mass of water produced from the complete combustion of 5.90×10−3 g of methane is 1.33 * 10^-2grams

5 0
1 year ago
For the reaction A+B↽−−⇀C+DA+B↽−−⇀C+D , assume that the standard change in free energy has a positive value. Changing the condit
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3 years ago
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