What us the motion? and what type of force did it experienced

I NEED HELP ASAP 1. Suppose a skydiver (mass = 75 kg) is falling toward the Earth. When the skydiver is 100 m above the Eart

ella [17]

PE = mgh

so (75kg)(9.8m/s2)(100m) = 73,500 Joules

KE = 1/2 m * v^2

so (1/2)(75kg)(60m/s)^2 = 135,000 Joules

ME = 208,500 Joules

5 0

2 years ago

If jack was traveling at 100 miles in 2 hours what was his speed in miles per minute?

Ludmilka [50]

Speed = (distance) / (time)

Speed = (100 mi/2 hr)

Multiply by a fraction equal to 1 :

Speed = (100 mi/2 hr) x (1 hr/60 min)

Speed = (100 x 1 / 2 x 60) (mi-hr/hr-min)

Speed = (100 / 120) (mi / min)

Speed = 5/6 mi/min

<em>Speed = 0.833... mi/min</em>

4 0

2 years ago

Interstellar dust causes stars to appear bluer than they actually are

ArbitrLikvidat [17]

Im not sure what your question is but I will just elaborate. Interstellar dust absorbs more red light than blue light, making stars appear bluer than their true color.

4 0

2 years ago

you push a box across the floor with a force of 30n you it 15 meters in 8 seconds. how much work did you do how much power did y

Naddika [18.5K]

20m/s newtons per second

7 0

2 years ago

Read 2 more answers

Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular alumin

Zarrin [17]

Answer:

$\rm 9.186\times 10^{-7}\ C.$

Explanation:

<u>Given:</u>

Diameter of the plates of the capacitor, D = 21 cm = 0.21 m.
Distance of separation between the plates, d = 1.0 cm = 0.01 m.
Minimum value of electric field that produces spark, $\rm E=3\times 10^6\ N/C.$

When the dimensions of the plate of the capacitor is comparatively much larger than the distance of separation between the plates, then, according to the Gauss' law of electrostatics, the value of the electric field strength in the region between the plates of the capacitor is given by

$\rm E=\dfrac{\sigma}{\epsilon_o}.$

where,

$\rm \sigma$ = surface charge density of the plate of the capacitor = $\dfrac qA$ .

$\rm q$ = magnitude of the charge on each of the plate.
$\rm A$ = surface area of each of the plate = $\rm \pi \times (Radius)^2=\pi \times\left ( \dfrac{D}{2}\right )^2= \pi \times \left ( \dfrac{0.21}{2}\right )^2=3.46\times 10^{-2}\ m^2.$
$\epsilon_o$ = electrical permittivity of free space, having value = $8.85\times 10^{-12}\rm \ C^2N^{-1}m^{-2}.$

For the minimum value of electric field that produces spark,

$\rm E = \dfrac{q}{A\epsilon_o}\\\Rightarrow q = E\ A\epsilon_o\\=3\times 10^6\times 3.46\times 10^{-2}\times 8.85\times 10^{-12}\\=9.186\times 10^{-7}\ C.$

It is the maximum value of the magnitude of charge which can be added up to each of the plates of the capacitor.

4 0

2 years ago

What us the motion? and what type of force did it experienced​

What us the motion? and what type of force did it experienced