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Troyanec [42]
3 years ago
6

Which of the following measurements is used to compare the distance between objects in the solar system? Distance between Earth

and Saturn Distance between the sun and Earth Speed of rotation of Saturn Speed of rotation of Earth
Physics
2 answers:
xxMikexx [17]3 years ago
8 0
Answer is: <span>Distance between the sun and Earth

Explanation:
</span><span>Distance between Earth and Saturn is not correct answer because this distance varies greatly. When comparing distance we need some distance that is pretty much the same all the times. This is why distance between the sun and Earth is chosen to meassure distances in solar system.
Answers "</span>Speed of rotation of Saturn" and "<span>Speed of rotation of Earth" are not correct because they represent speed which can not measure distance.</span>
hammer [34]3 years ago
5 0

Answer:

Distance between earth and sun.

Explanation:

The distance between earth and sun is used to compare the distance between the objects in our solar system. It is because the distance between earth and sun is called as one Astronomical unit.

1 Astronomical unit (AU) is equal to 149,597,870.7 Km.

It is the mean distance between earth and sun.

The time taken by light to cover 1 Astronomical Unit is 499 seconds.

This is a big unit of distance.

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What is the frequency of a photon with an energy of 4. 56 x 10^-19 j
Sauron [17]

The frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.

<h3>What is a frequency?</h3>

The number of waves that travel through a particular point in a given length of time is described by frequency. So, if a wave takes half a second to pass, the frequency is 2 per second.

Given that the energy of the photon is 4.56 x 10⁻¹⁹ J. Therefore, the frequency of the photon can be written as,

\rm \gamma = \dfrac{E}{h} = \dfrac{4.56x10^{-19} J}{6.626 \times 10^{-34}\ Jsec^{-1}}\\\\\\\gamma  = 6.88 \times 10^{14}\ s^{-1}

Hence, the frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.

Learn more about Frequency:

brainly.com/question/5102661

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5 0
2 years ago
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Why does cold weather feel colder inside?
schepotkina [342]
One reason is that when you have been out in the cold, your hands feet and exposed features of your face will take time to recover as the blood circulation improves and supplied warm blood to capillaries. So the relatively warm room you enter will not immediately feel warm until the blood has regained its normal circulation. Other factors are that windows are cooled from the outside and condensation forms on the inside because of moisture in the air. For this condensation to evaporate requires heat, which will be extracted from the room and the air near the windows will be cooled. The cold air will descend and form a draught at floor level and this will tend to make the room cooler.
8 0
3 years ago
What is the energy in joules of a photon with a frequency of 3.16e 12 s-1?
erica [24]
We have: Energy(E) = Planck's constant(h) × Frequency(∨)
Here, Planck's constant(h) = 6.626 × 10⁻³⁴ J/s
Frequency (∨) = 3.16 × 10¹² /s

Substitute the values into the expression:
E = (6.626 × 10⁻³⁴)(3.16 × 10¹²) J
E = 2.093 × 10⁻²¹ Joules

In short, Your Final answer would be 2.093 × 10⁻²¹ J

Hope this helps!
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3 years ago
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They interact with one another with their facial expressions and body movements all the time
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Second and third class levers are differentiated by __________. a. the location of the fulcrum b. the location of the load c. th
strojnjashka [21]

Answer:

the answer is b

Explanation:

Second and third class levers are differentiated by <u>the location of the </u><u>load.</u>

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