A galvanic cell is formed when two metals are immersed in solutions differing in concentration 1 when two different metals are immersed.
<h3>What is galvanic cell?</h3>
A galvanic cell is an electrochemical device that transforms chemically generated free energy into electrical energy. A photogalvanic cell produces photochemical species that react to produce an electrical current when connected to an external circuit.
<h3>How does galvanic cell works?</h3>
In order to create a pathway for the flow of electrons via this wire, the galvanic cell makes use of the ability to split the flow of electrons during the processes of oxidation and reduction, forcing a half-reaction and linking each with a wire.
An electrochemical device known as a galvanic cell converts chemical energy from a spontaneous redox response into electrical energy. It possesses an electrical potential of 1.1 V. The anode, which is a negative plate in galvanic cells, is where oxidation takes place. It is a positive plate where lessening takes place.
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Answer:
D
Explanation:
I believe it is D. your kinetic energy would be at b. A, the cart would be going at a constant rate, because there is no hill or steep slope.
<span>P*V/T=constant
so P*V= constant*T
if T doesn't change then
P*V= constant
so 150kPa*0.8L=75kPa*xL
xL=150kPa*0.8L/75kPa=1.6L
hope it help</span>
Answer:
mass I hope can help this answer
Explanation:
keep on learning
Answer:
The concentration of species in 500 mL of a 2.104 M solution of sodium sulfate is 4.208 M sodium ion and 2.104 M sulfate ion. (option E)
Explanation:
Step 1: Data given
Volume = 500 mL = 0.500 L
The concentration sodium sulfate = 2.104 M
Step 2: The equation
Na2SO4 → 2Na+ + SO4^2-
For 1 mol Na2SO4 we have 2 moles sodium ion (Na+) and 1 mol sulfate ion (SO4^2-)
Step 3: Calculate the concentration of the ions
[Na+] = 2*2.104 M = 4.208 M
[SO4^2-] = 1*2.104 M = 2.104 M
The concentration of species in 500 mL of a 2.104 M solution of sodium sulfate is 4.208 M sodium ion and 2.104 M sulfate ion. (option E)
