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Tom [10]
3 years ago
9

An element has four naturally occurring isotopes with the masses and natural abundances given here. find the atomic mass of the

element. isotope mass (amu) abundance (%) 1 135.90714 0.1900 2 137.90599 0.2500 3 139.90543 88.43 4 141.90924 11.13
Chemistry
1 answer:
sergeinik [125]3 years ago
6 0
<span>Abundance of each isotope = 0.1900 x100 = 0.001900
</span><span>0.2500 = 0.002500
</span><span>88.43 =  0.8843
</span>11.13 = 0.1113
Atomic mass of the element = (<span>135.90714  x 0.001900</span>) + (<span>137.90599 x 0.002500</span>) + (<span>139.90543 x 0.8843</span>) + (<span>141.90924 x 0.1113</span>)
= 0.258223566 + 0.344764975 + 123.718371749 + 15.794498412
= 140.1 amu is the atomic mass of the element
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