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disa [49]
3 years ago
15

How will the number of neutrons in an atom impact its stability?

Chemistry
1 answer:
astraxan [27]3 years ago
6 0
                                                                                                                                    <span>Neutrons emit residual strong force without electric charge. This is why they have a stabilization effect. It is an interplay between the two particles which stabilize the nucleus.</span>   so the neutrons play a big role in the stability process.                 
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BRAINLIEST ASAP!!! Help
Andru [333]

Answer:

N2C14

Explanation:

<em> determined the bond type by looking if it is a metal or nometal</em>

<em>Ionic Bond:NM+M</em>

<em>Covalent Bond:NM+NM</em>

7 0
3 years ago
Calculate the Molarity when a 6.11 mL solution of 0.1 H2SO4 is diluted with 105.12 mL of water
barxatty [35]

Molarity after dilution : 0.0058 M

<h3>Further explanation </h3>

The number of moles before and after dilution is the same  

The dilution formula

 M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

M₁=0.1 M

V₁=6.11

V₂=105.12

\tt M_2=\dfrac{M_1.V_1}{V_2}=\dfrac{0.1\times 6.11}{105.12}=0.0058~M

5 0
3 years ago
If Bert the Bat travels eastward at 540 mph with a tail wind of 6 mph. What is his actual speed?
miskamm [114]

Answer:

12 mph

Explanation:

6 0
3 years ago
Read 2 more answers
4. A student started with a 0.032 g sample of copper which he took through the series of reactions described in this experiment.
Elodia [21]

Answer:

Y=48.6\%

Explanation:

Hello,

In this case, we can consider the following chemical reaction for the oxidation of copper which only occurs at high temperatures:

2Cu+O_2\rightarrow 2CuO

In such a way, for 0.032 grams of copper, the following grams of copper (II) oxide (black product) are yielded:

m_{CuO}=0.032gCu*\frac{1molCu}{63.546gCu} *\frac{2molCuO}{2molCu}*\frac{79.546gCuO}{1molCuO}  =0.078gCuO

Therefore, the percent yield is:

Y=\frac{0.038g}{0.078g}*100\%\\ \\Y=48.6\%

Best regards.

6 0
3 years ago
Which of the following breaks and forms bonds?
svp [43]
Your answer would be "Chemical Change"
7 0
3 years ago
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