Answer:
N2C14
Explanation:
<em> determined the bond type by looking if it is a metal or nometal</em>
<em>Ionic Bond:NM+M</em>
<em>Covalent Bond:NM+NM</em>
Molarity after dilution : 0.0058 M
<h3>Further explanation
</h3>
The number of moles before and after dilution is the same
The dilution formula
M₁V₁=M₂V₂
M₁ = Molarity of the solution before dilution
V₁ = volume of the solution before dilution
M₂ = Molarity of the solution after dilution
V₂ = Molarity volume of the solution after dilution
M₁=0.1 M
V₁=6.11
V₂=105.12

Answer:

Explanation:
Hello,
In this case, we can consider the following chemical reaction for the oxidation of copper which only occurs at high temperatures:

In such a way, for 0.032 grams of copper, the following grams of copper (II) oxide (black product) are yielded:

Therefore, the percent yield is:

Best regards.
Your answer would be "Chemical Change"