Answer:
The answer to your question is: third option is correct.
Step-by-step explanation:
The third option is correct
4(-2)⁻²(4)⁻³
<span>%Antifreeze=<span><span>V<span>Antifreeze</span></span><span>V<span>Fluid</span></span></span></span>
<span><span>V<span>Fluid</span></span>=<span><span>V<span>Antifreeze</span></span><span>%Antifreeze</span></span></span>
<span><span>V<span>Antifreeze</span></span>=<span>V<span>fluid</span></span>∗%Antifreeze</span>
I want to find the amount of antifreeze in a 15 quart solution with 30% antifreeze
<span><span>V<span>Antifreeze</span></span>=15∗0.30</span> =18/4 quarts of antifreeze
Similarly, I want to find the amount of antifreeze in a 15 quart solution with 35% antifreeze first.
<span><span>V<span>Antifreeze</span></span>=15∗0.35</span> = 21/4 quarts of antifreeze
<span>the difference between 21/4 and 18/4 is 3/4 quarts, which is the amount of pure antifreeze I've added in.
</span><span>
SO the V_fluid I replaced with 3/4 quarts of antifreeze is (3/4)/ 0.35</span>
Answer:
slope: -1/2
y-intercept: -2
Step-by-step explanation:
f(x) = mx+b
m is slope
b is the y-intercept
so
if f(x) = -1/2x - 2
then
the slope or m is -1/2
and the y-intercept or b is -2
Answer:
Fifty percent of the data values lies between 34 and 46.
It is unlikely that there are any outliers.
Step-by-step explanation:
drawing out this box plot and looking online for a picture of the same plot:
From the box plot:
median=46
Q1=42
Q3=70
Q3-Q1= IQR=70-42=28
max=76
min=34
Range=max-min=76-34=42
no outliers seen from boxplot
Yes I think so because she write 42 per minute the question doesn't tell you anything else.
I am not sure :(
