What is 110.4 x 10.2 rounded to the nearest whole number

Mathematics

1 answer:

nexus9112 [7]3 years ago

4 0

Answer:

1,126 or 1100

Step-by-step explanation:

This is the answer because:

1) 110.4 x 10.2 is equal to 1,126.08

2) 1,126.08 rounded to the nearest whole number is 1,126 because the number before 6 is is 0 which makes the number stay the same

3) The answer can also be 1100 because you first have to round 110.4 and 10.2 to the nearest whole numbers which will get you 110 and 10 since the rounding numbers are below 5

3) Then, multiply 110 and 10 which is 1100

Hope this helps!

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Show that the equation x^4/2021 − 2021x^2 − x − 3 = 0 has at least two real roots.

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The roots of an equation are simply the x-intercepts of the equation.

See below for the proof that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ has at least two real roots

The equation is given as: $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$

There are several ways to show that an equation has real roots, one of these ways is by using graphs.

See attachment for the graph of $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$

Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)

From the attached graph, we can see that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500

This means that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ has at least two real roots

Read more about roots of an equation at:

brainly.com/question/12912962