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3 years ago

2. A race car rounding a corner at a constant speed of 200 miles per hour. Yes not

Physics

2 answers:

nirvana33 [79]3 years ago

7 0

Answer:

what is the question in "2. A race car rounding a corner at a constant speed of 200 miles per hour. Yes not"

mash [69]3 years ago

6 0

I don’t understand your question

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Investigators are researching the appearance of a strange movement of objects in what the local community considers a haunted ho

wolverine [178]

Answer:

0.18216 T

Explanation:

N = Number of turns = 219

A = Area = $\pi r^2$

r = Radius = 1 cm

$\omega$ = Angular speed = $40\times 2\pi$

Maximum emf is given by

$\epsilon=NBA\omega\\\Rightarrow B=\dfrac{\epsilon}{NA\omega}\\\Rightarrow B=\dfrac{3.15}{219\times \pi 0.01^2\times 40\times 2\pi}\\\Rightarrow B=0.18216\ T$

The strength of the magnetic field is 0.18216 T

8 0

3 years ago

The closest distance a book can be read from a pair of reading eyeglasses (Power = 1.55 dp) is 26.0 cm. What is the near distanc

Mnenie [13.5K]

Answer:

The image distance is 20.0 cm.

Explanation:

Given that,

Power = 1.55 dp

Distance between book to eye = 26.0+3.00=29.0 cm

We need to calculate the focal length

Using formula of focal length

$f = \dfrac{1}{P}$

Put the value into the formula

$f=\dfrac{1}{1.55}$

$f=0.645\ m$

$f=64.5\ cm$

We need to calculate the image distance

Using lens formula

$\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}$

$\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{-u}$

Put the value into the formula

$\dfrac{1}{v}=\dfrac{1}{64.5}-\dfrac{1}{-29}$

$\dfrac{1}{v}=\dfrac{187}{3741}$

$v=20.0\ cm$

Hence, The image distance is 20.0 cm.

5 0

3 years ago

PLEASE HELP NOT A LOT OF TIME LEFT!!!!!

GenaCL600 [577]

D. 65.1 is the answer

8 0

3 years ago

You have an incident ray from a medium with a n1=1, through a medium with a n2 =3.325. If the incident angle is equal to 0.478 r

sesenic [268]

Answer:

0.139 rad

Explanation:

We use Snell's law $n_1sin\theta_1=n_2sin\theta_2$ , where if $n_1$ is the refractive index of the medium containing the incident ray, $\theta_1$ would be the incident angle, and if $n_2$ is the refractive index of the medium containing the refracted ray, $\theta_2$ would be the refraction angle, which we want, so we do:

$sin\theta_2=\frac{n_1}{n_2}sin\theta_1$

And finally:

$\theta_2=arcsin(\frac{n_1}{n_2}sin\theta_1)$

We then insert our values:

$\theta_2=arcsin(\frac{n_1}{n_2}sin\theta_1)=Arcsin(\frac{1}{3.325}sin(0.478rad))=arcsin(0.13834714686
)=0.139 rad$

6 0

3 years ago

Three out of four crashes happen at a speed of __________ miles per hour or less.

Nitella [24]

The answer is 45 miles per hour or even less. Most crashes occur at a speed of 45 miles per hour or even less, and most of these accidents occur close to our homes. These crashes may also be caused by different factors, such as being drunk or sudden occurrences that are not controllable, which is why it is best to precede with caution when driving at crowded areas.

5 0

3 years ago