Suppose you throw a ball straight upward; it rises, then returns to your hand

Physics

1 answer:

bazaltina [42]3 years ago

5 0

Answer:

Please find the attached file for the solution

Explanation:

Given that you throw a ball straight upward; it rises, then returns to your hand

(a) Calling the point where it leaves your hand the origin and upward positive, make a plausible sketch of its position (vertical height) x(t) versus time t from the instant after it leaves your hand till the instant before it reaches it again.

(b) From your x(t) plot, make a sketch of the ball’s velocity v(t) versus time.

(d) Does your plot suggest that the ball’s acceleration is zero at the top of its flight

Please find the attached file for the solution and graph

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How much faster does sound travel in the ocean been in the rain forest?show your work.

Natasha2012 [34]

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4 years ago

Three resistors are wired in parallel with a battery. Two of the resistors have resistances of 38.7 Q/ and 89.5 Q. The current i

Lina20 [59]

Answer:

$214.9 \Omega$

Explanation:

The three resistors are connected in parallel: this means that the potential difference across each resistor is the same as the voltage of the battery. This can be calculated using the information about the $38.7 \Omega$ resistor: in fact, since we know its resistance and the current flowing through it (0.155 A), we can find the potential difference across this resistor, which is equal to the voltage of the battery:

$V=IR=(0.155 A)(38.7 \Omega)=6.0 V$

We also know the total current in the circuit, 0.250 A. This means that we can find the total resistance of the circuit, using Ohm's law:

$R_{eq}=\frac{V}{I}=\frac{6.0 V}{0.250 A}=24 \Omega$

So now we now the total resistance and the resistance of two of the 3 resistors; therefore, we can find the resistance of the 3rd resistor:

$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}\\\frac{1}{R_3}=\frac{1}{R_{eq}}-\frac{1}{R_1}-\frac{1}{R_2}=\frac{1}{24 \Omega}-\frac{1}{38.7\Omega}-\frac{1}{89.5\Omega}=0.00465 \Omega^{-1}\\R_3=\frac{1}{0.00465 \Omega^{-1}}=214.9 \Omega$