The answer is A lithium sulfite
Answer:
D. the quantity of heat that is required to raise 1 g of the sample by 1*C (kelvin) at a constant pressure.
Answer:

Explanation:
Hello!
In this case, when two substances at different temperature are put in contact and an equilibrium temperature is attained, we can evidence that the heat lost by the hot substance (metal) is gained by the cold substance (water) and we can write:

Which can be also written as:

Thus, since we need the specific heat of the metal, we solve for it as shown below:

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Answer: Volatile
Explanation:
like ethanol(alcohol) it evaporates when you put it in the hand, really fast.
Some people think that it dries when it really evaporated at room temperature from liquid to gas
Answer:
A mixture of solid particles and gases in the air.
Explanation:
Air pollution is a mixture of solid particles and gases in the air. car emissions, chemicals from factories, dust, pollen and mold spores may be suspended as particles. Ozone, a gas, is a major part of air pollution in cities. When ozone forms air pollution, it's also called smog.