<span>At a corner gas station, the revenue R varies directly with the number g of gallons of gasoline sold. If the revenue is $44.50 when the number of gallons sold is 10, find a linear equation that relates revenue R to the number g of gallons of gasoline. Then find the revenue R when the number of gallons of gasoline sold is 15.5.
Solution:
As the question mentioned the direct relationship between the quantities, hence
10 gallons of gasoline sold = $44.50
15.5 gallons of gasoline sold = $x
by cross multiplication, we get that
10x = 15.5 * 44.50
which implies that
x = 68.975
Thus by $</span>68.975 revenue is obtained by selling 15.5 gallons of gasoline.
1. it’s saying 2-6 which is -4
2. it’s saying -6-5 which is -11
For this fraction, you would have to see how many times 7 goes into 47. So, 6 times as 7 times 6 is 42. Subtract 42 from 47, and this would be your remainder:
6
Answer:
It is not possible to solve the equation y = 4x + 3. This is merely a relation between two variables x and y. The variable y is 3 greater than 4 times the variable x.
Step-by-step explanation:
What book?
